Question

Using Hooke's Law, you find the spring constant of a given spring to be 8.0 N/m 0.6 N/m. Your lab partner uses simple harmonic motion and finds the spring constant to be 8.9 N/m 0.5 N/m. Would you consider these two springs to have the same spring constant?
a. yes

b. no

c. not enough info

Answer 1

Answer:Yes

Explanation:

Given

Using Hooke's law value of spring constant is

$k_1=8 N/m$

$k_2=0.6 N/m$

so the range of k varies from $k_1-k_2\ to\ k_1+k_2$

i.e. from 8-0.6 to 8+0.6=7.4 to 8.6 N/m

From SHM experiment

Spring constant obtained are

$k_a=8.9 N/m$

$k_b=0.5 N/m$

range $=k_a-k_b\ to\ k_a+k_b$

range=8.9-0.5  to 8.9+0.5

range=8.4 to 9.4 N/m

as both range is coinciding at some Point therefore it can be consider that the spring is same