Answer:
V = 20.5 m/s
Explanation:
Given,
The mass of the cart, m = 6 Kg
The initial speed of the cart, u = 4 m/s
The acceleration of the cart, a = 0.5 m/s²
The time interval of the cart, t = 30 s
The final velocity of the cart is given by the first equation of motion
v = u + at
= 4 + (0.5 x 30)
= 19 m/s
Hence the final velocity of cart at 30 seconds is, v = 19 m/s
The speed of the cart at the end of 3 seconds
V = 19 + (0.5 x 3)
= 20.5 m/s
Hence, the final velocity of the cart at the end of this 3.0 second interval is, V = 20.5 m/s
Answer:
B. Same for a chemical family
Answer:
The angle that the wave would be 
Explanation:
From the question we are told that the opening to the harbor acts just like a single-slit so a boat in the harbor that at angle equal to the second diffraction minimum would be safe and the on at angle greater than the diffraction first minimum would be slightly affected
The minimum is as a result of destructive interference
And for single-slit this is mathematically represented as

where D is the slit with
is the angle relative to the original direction of the wave
m is the order of the minimum j
is the wavelength
Now since in the question we are told to obtain the largest angle at which the boat would be safe
And the both is safe at the angle equal to the second minimum then
The the angle is evaluated as
![\theta = sin ^{-1}[\frac{m\lambda}{D} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20sin%20%5E%7B-1%7D%5B%5Cfrac%7Bm%5Clambda%7D%7BD%7D%20%5D)
Since for second minimum m= 2
The equation becomes

Answer:
Explanation:
initial velocity v = 2.1 x 10⁷ m/s
acceleration a = 5.1 x 10¹⁵ m /s²
horizontal distance covered = 5.5 x 10⁻² m
time taken to cover horizontal distance = 5.5 x 10⁻² / 2.1 x 10⁷
= 2.62 x 10⁻⁹ s .
b )
vertical distance travelled due to vertical acceleration
= 1/2 a t²
= .5 x 5.1 x 10¹⁵ x (2.62 x 10⁻⁹)²
= 17.5 x 10⁻³ m