The answer for this question is Control Variable because it doesn’t change throughout the experiment.
Answer:
T₂ = 20.06 ° C
Explanation:
Given
P = 90 kg, T₁ = 20 ° C, h = 30 m, c = 1.82 kJ / Kg * ° C
Using the formula to determine the final temperature of the water
T₂ = T₁ * P * h / Eₐ * c
The work done of the person to the water
Eₐ = 1000 kg / m³ * 5 m³ * 9.8 m / s²
Eₐ = 49000 N
T₂ = 20 ° C +[ (90 kg * 30m) / (49000 N * 1.82) ]
T₂ = 20.06 ° C
Answer:
It is the ratio of the density of a substance to the density of a given reference material.
Explanation:
<em>Specific gravity is also known as relative density.</em>
<u>To find the relative density of substance, you:</u>
- Divide the density of substance measured
- And divide that by the density of the reference
160 m/s because you start off with 10 and go up by 50*3 which is 150 then add that with the begging speed to achieve 160m/s.
Answer:
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Explanation:
