Need help on question b

Resistors 1 and 2− R1 = 50 Ω , R2 = 90 Ω − are connected in series to a 6.0-V battery. Part APart complete What is the potential

kondor19780726 [428]

Answer:

Part A: The voltage across resistor R1 is approximately $\rm 2.1 \; V$ .

Part B: When the value of resistor R1 decreases, the current in this circuit will increase.

Part C: When the value of resistor R1 decreases, the voltage across resistor R1 will decrease.

Explanation:

Resistor R1 and and R2 are connected in series. That's equivalent to a single resistor of $R_1 + R_2 = 50 + 90 = 140\; \Omega$ . The voltage across the two resistor, combined, is equal to $\rm 6\; V$ . Hence by Ohm's Law, the current through the circuit will be equal to $\rm \dfrac{6\; V}{140\; \Omega} = \dfrac{3}{70}\; A$ .

These two resistors are connected in series. The voltage across each of them might differ. However, the current through each of them should both be equal to the current through the circuit. In this case, the current through both R1 and R2 should be equal to $\rm \dfrac{3}{70}\; A$ . Apply Ohm's Law (again) to find the voltage across R1:

$V = I \cdot R = \dfrac{3}{70} \times 50 \approx \rm 2.1\; V$ .

Since the equivalent resistance is equal to $R_1 + R_2$ , when the value of $R_1$ decreases, the equivalent resistance will also decrease. By Ohm's Law, $I = \dfrac{V}{R}$ . When the value of the denominator ( decreases, the value of the quotient, $I$ the current through the circuit, will increase.

Keep in mind that if two resistors are connected in series,

$I(R_1) = I(\text{Circuit}) = I(R_2)$ .

The resistance of R1 decreases, while the current through it increases. Applying Ohm's Law on R1 won't give much useful information. However, since the resistance of R2 stays the same, the voltage across it will increase when its current increases (again by Ohm's Law.)

Again, since the two resistors are connected in series,

$V(R_1) + V(R_2) = V(\text{Circuit}) = \rm 6 \; V$ ,

when the voltage across R2 increases, the voltage across R1 will decrease.

4 0

3 years ago

What is the defining characteristic of a water cycle?

pav-90 [236]

<span>It has the same starting and ending point</span>

7 0

3 years ago

Two students are discussing the Sun. Which student is correct? Student 1: Nuclear fusion powers the Sun, so activity like sunspo

timofeeve [1]

Answer:

Both student are correct.

Explanation:

Given :

Student 1: Nuclear fusion powers the Sun, so activity like sunspots and flares must be caused by a change in the fusion rate or the type of fusion.

Student 2: Fusion is constant, keeping the Sun a nice temperature; changes on the surface are caused by the Sun's magnetic field

There are two types of nuclear reaction,

Fusion:

Two lighter atom combine together are produce new atom.

In case of fusion large amount of energy produces and fusion powers the sun. In case of sun two hydrogen atom combine together and helium produces so statement 1 is true.

Sun posses large magnetic field due to magnetic field sun spot created like magnet there are two poles N and S, magnetic field lines goes from N to S.

Sun spot are produces because of change in magnetic field and change in temperature. So statement 2 is also true.

3 0

3 years ago

Suppose a pendulum starts with a potential energy of 100 J. Assuming the pendulum has a height of 0 m at the bottom of its swing

WINSTONCH [101]

Answer:

The maximum kinetic energy is 100 Joules

Explanation:

Considering the pendulum as an isolated system, the kinematic energy will be conserved. The kinematic energy = (potential energy) + (kinetic energy). We know that it starts at rest (i.e., with kinetic energy being 0) with 100 Joules worth of potential energy. We also know that when the pendulum crosses the bottom point at 0m it has potential energy of 0 J implying its kinetic energy is 100 J, which is its maximum.

4 0

3 years ago

While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find th

Eduardwww [97]

Answer:

$\omega = 0.273 rad/s$

$v = 3.825 m/s$

Explanation:

Assuming that the question is asking for the angular and linear speed of the Ferris wheel, we can solve by converting from period of 1 revolution (23 s) to angular speed knowing that 1 revolution would sweep and angle of 2π.

$\omega = \frac{2\pi}{T} = \frac{2\pi}{23} = 0.273 rad/s$

We can calculate the linear speed of the motion from the angular speed and the radius

$v = \omega r = 0.273 * 14 = 3.825 m/s$

4 0

4 years ago