Reaction equation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
Moles of Al(OH)₃:
moles = mass/Mr
= 1.51 / (27 + 17 x 3)
= 0.019
Molar ratio Al(OH)₃ : HCl = 1 : 3
Moles of HCl required = 0.019 x 3
=0.057
concentration = moles/volume
volume = 0.057 / 0.1
= 0.57 dm³
= 570 ml
Answer: The correct answer is option B i.e., 2.78 mol
Explanation:
Aluminium reacts with iodine to form Aluminium iodide
From the equation, it is clear that 3 moles of iodine reacts with 2 moles of Aluminium to form Aluminium iodide
We know 
For 2 moles of Aluminium, 
3 moles of Iodine reacts with 54 g of Aluminium
? moles of iodine react with 50 g of Aluminium
Answer:
I have no clue what is being asked in the second half of the question. Is there some context from which the question is taken?
Explanation:
If the temperature of the water an ice cube is placed in is <u>___above 0°C__</u>, then the ice cube will melt <u>_unless you remove it??_________</u>.
<span>What is the atomic number of the first element to start filling an "f" sub-level?
the answer is 58.
I hope this helps :)</span>
