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3 years ago

What is the overall trend for ionization energy on the periodic chart?

Chemistry

2 answers:

gizmo_the_mogwai [7]3 years ago

7 0

Answer:

The general trend is for ionization energy to increase moving from left to right across an element period. Moving left to right across a period, atomic radius decreases, so electrons are more attracted to the (closer) nucleus.

Explanation:

Brainliest plz

pogonyaev3 years ago

7 0

Answer:

Ionization energy increases across the period and decreases down the group.

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What does homogeneous mixture of elements mean

mina [271]

If a substance is not chemically pure, it is either a heterogeneous mixture or a homogeneous mixture. If its composition is uniform throughout, it is a homogeneous mixture.

8 0

3 years ago

The reaction C 4 H 8 ( g ) ⟶ 2 C 2 H 4 ( g ) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ / mol. 262 kJ/mol. At 600.0 K,

ludmilkaskok [199]

Answer: $4.3\times 10^{-13}s^{-1}$

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $600.0K$ = $6.1\times 10^{-8}s^{-1}$

$K_2$ = rate constant at $775.0$ = $?$

$Ea$ = activation energy for the reaction = 262 kJ/mol = 262000J/mol

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = $600.0K$

$T_2$ = final temperature = $775.0K$

Now put all the given values in this formula, we get

$\log (\frac{6.1\times 10^{-8}}{K_2})=\frac{262000}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{775.0K}]$

$\log (\frac{6.1\times 10^{-8}s^}{K_2})=5.150$

$(\frac{6.1\times 10^{-8}}{K_2})=141253.8$

Therefore, the value of the rate constant at 775.0 K is $4.3\times 10^{-13}s^{-1}$

5 0

3 years ago

Please awnser the fill in blanks don’t mind the top or bottom pls help !!!!

zysi [14]

Can’t see the problems

7 0

3 years ago

What is the equilibrium constant of pure water at 25°C?

ANEK [815]

The equilibrium reaction, causes the water dissociation constant, Kw, is 1.01 × 10-14 at 25 °C. That is because every H+ (H3O+) ion these forms accompanied by the formation of an OH- ion, are the concentrations of these ions and in pure water the same thing can be calculated from Kw.

HOPED THIS HELP OUT ;)

6 0

3 years ago

Read 2 more answers

A solution contains one or more of the following ions: Ag , Ca2 , and Co2 . Lithium bromide is added to the solution and no prec

koban [17]

Answer:

$Ca^{2+} and Co^{2+}$