-58 °C
The melting point is the same as the freezing point.
Answer : The final temperature of the copper is, 
Solution :
Formula used :

where,
Q = heat gained = 299 cal
m = mass of copper = 52 g
c = specific heat of copper =
= final temperature = ?
= initial temperature = 
Now put all the given values in the above formula, we get the final temperature of copper.


Therefore, the final temperature of the copper is, 
A neutron is neutral and a proton is positive and a electron is negative
Answer: Option (e) is the correct answer.
Explanation:
Chemical formula of a nitrate ion is
and it acts as a strong oxidizing agent because it itself gets reduced easily.
As we know that an oxidizing agent tends to oxidize other substances by itself gaining electrons. As a result, there will occur a decrease in its oxidation state.
The oxidation number of nitrogen in
is +5. So, it gains electrons and helps in oxidizing other substances.
Thus, we can conclude that the nitrate anion is a strong oxidizing agent.