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pishuonlain [190]
3 years ago
12

Adding copper or magnesium to aluminum creates an alloy that is _____. more flammable than magnesium heavier than steel stronger

than aluminum
Chemistry
2 answers:
Maksim231197 [3]3 years ago
5 0

stronger than aluminum

Tasya [4]3 years ago
3 0

Answer:

The given blank can be filled with stronger than aluminium.

Explanation:

The metals, which have been mixed with other elements or metals to obtain new characteristics are known as alloys. The metal alloys generally provide more durability, greater strength, and flexibility over the base metal. One of the prime advantages of a metal alloy is that it can strengthen metal or can minimize cost, and at the same time sustaining some of its own substantial characteristics.  

In aluminum alloys, aluminum is the main metal amalgamated with magnesium, zinc, copper, or other metals.  

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What are the mole fraction and the mass percent of a solution made by dissolving 0.21 g KBr in 0.355 L water? (d = 1.00 g/mL.) m
IRISSAK [1]

Answer:

Mol fraction H2O = 0.99991

Mol fraction KBr = 0.00009

mass % KBr = 0.059 %

mass % H2O = 99.941 %

Explanation:

Step 1: Data given

Mass of KBr = 0.21 grams

Molar mass KBr = 119 g/mol

Volume of water = 355 mL

Density of water = 1.00 g/mL

Molar mass water = 18.02 g/mol

Step 2: Calculate mass water

Mass water = 355 mL * 1g /mL

Mass water = 355 grams

Step 3: Calculate moles water

Moles water = mass water / molar mass water

Moles water = 355 grams / 18.02 g/mol

Moles water = 19.7 moles

Step 4: Calculate moles KBr

Moles KBr = 0.21 grams / 119 g/mol

Moles KBr = 0.00176 moles

Step 5: Calculate total moles

Total moles = 19.7 moles + 0.00176 moles

Total moles = 19.70176 moles

Step 6: Calculate mol fraction

Mol fraction H2O = 19.7 moles / 19.70176 moles

Mol fraction H2O = 0.99991

Step 7: Calculate mol fraction KBr

Mol fraction KBr = 0.00176 / 19.70176

Mol fraction KBr = 0.00009

Step 6: Calculate mass %

mass % KBR = (0.21 grams / (0.21 + 355) grams) *100%

mass % KBr = 0.059 %

mass % H2O = (355 grams / 355.21 grams) *100%

mass % H2O = 99.941 %

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Answer:

You would get 19.969 moles

Explanation:

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