Question

- To approach the runway, a small plane must begin a 6° descent starting from a height of 1297 feet above the

Answer 1

Step-by-step explanation:

Use the equation: sin(Theta)=opposite/ hypotenuse

X shows the how far from approach

so sin(26)=1297/x

rearrange to make: X=1125/sin(26

so 1125/sin(26)= 2,566.3 miles

Therefore, it will be 2,566.3 miles from approach

hope this helps :)

Have a nice day