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The sum of 5 consecutive odd integers is 2,555. What is the sum of the first, third, and last integer?

Lilit [14]

Answer:

The sum of the first, third, and last integer is 1533.

Step-by-step explanation:

Step 1: You need to create a equation first:

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

How did I make the equation?

If n is odd number, n + 2 must be the consecutive odd number

5 , 5 + 2 , 5 + 4 , 5 + 6 , 5 + 8

5, 7, 9, 11, 13 ALL CONSECUTIVE ODD NUMBERS

Step 2: Simplifying the equation

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

5n + 20 = 2555

Step 3: Solving the equation, with explanation

5n + 20 = 2555 Subtract 20 on both sides

5n = 2535 Isolate the variable by dividing 5 on both sides

n = 507

Step 4: Plug in the value

n + n + 2 + n + 4 + n + 6 + n + 8

507, 507 + 2 , 507 + 4 , 507 + 6 , 507 + 8

507, 509, 511, 513, 515

Step 5: Solve the sum of the first, third, and last integer

507 + 511 + 515 = 1533

Step 6: THE ANSWER

1533

<h3>Hope this helps!!! </h3><h3>Please mark this as brainliest!!! </h3><h3>Thank You!!! </h3><h3>:)</h3>

8 0

3 years ago

Which number is greater: 35% or 3.5?

Lunna [17]

Answer: 3.5

Step-by-step explanation:

3 0

3 years ago

Solve the equation for the given variable. justify each step.

s344n2d4d5 [400]

Answer: y= $\frac{5-9x}{2}$

s=-30+10t

Step-by-step explanation:

9x + 2y = 5; y

9x-9x+2y = 5-9x

2y=5-9x

y= $\frac{5-9x}{2}$

1/15s - 2/3t = -2; s

(1/15s - 2/3t = -2)*15 ==> Get rid of fraction by multiplying both sides by 15

s - 30/3 t=-30

s-10t=-30

s=-30+10t

5 0

2 years ago

2. What is the minimum value of of the function below

vovangra [49]

What is the minimum value of of the function below y = 2x2 – 8x + 11 O y=-3 O y = 2 O y = 3 O y = 11

4 0

3 years ago

Co-ordinate Geometry

saul85 [17]

Answer:

The value of a = 14

Step-by-step explanation:

Given

(x₁, y₁) = (2, 4)

(x₂, y₂) = (6, a)

(x₃, y₃) = (-1, 1)

A = 9 sq.units

Area of a triangle with vertices (x₁, y₁), (x₂, y₂), and (x₃, y₃) is:

$A=\frac{\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|}{2}$

substituting the values (x₁, y₁) = (2, 4), (x₂, y₂) = (6, a), (x₃, y₃) = (-1, 1), A = 9 in th formula

$A=\frac{\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|}{2}$

$9=\frac{\left|2\left(a-1\right)+6\left(1-4\right)+-1\left(4-a\right)\right|}{2}$

Multiply both sides by 2

$\frac{2\left|2\left(a-1\right)+6\left(1-4\right)-1\left(4-a\right)\right|}{2}=9\cdot \:2$

simplify

$\left|2\left(a-1\right)+6\left(1-4\right)-1\left(4-a\right)\right|=18$

As the area is always positive.

so

$2\left(a-1\right)+6\left(1-4\right)-1\cdot \left(4-a\right)=18$

$2\left(a-1\right)-18-\left(4-a\right)=18$

Add 18 to both sides

$2\left(a-1\right)-18-\left(4-a\right)+18=18+18$

simplify

$2\left(a-1\right)-\left(4-a\right)=36$

$3a-6=36$

$3a=42$

Divide both sides by 3

$\frac{3a}{3}=\frac{42}{3}$

$a=14$

Thus, the value of a = 14

7 0

3 years ago