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3 years ago

7

How would amperage and voltage affect the power of the fence

1 answer:

e-lub [12.9K]3 years ago

8 0

So it's easier to break amps and volts down as if they were water through a pipe. Voltage is the pressure at which the water is forced through so you can survive high voltage. While Amperes would be the amount or volume of water that flows out over a period of time it doesn't take much amps to kill you as goes the saying "amps give the cramps and volts give the jolts"

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What material structure explanation lies behind the fact that the propagation velocity of longitudinal waves is the lowest in ga

Lina20 [59]

Answer:

What material structure explanation lies behind the fact that the propagation velocity of longitudinal waves is the lowest in gases and the highest in solids?

8 0

3 years ago

1<br> A truck increases its speed from 15 m/s to 60 m/s in 15 s. Its acceleration is

MAVERICK [17]

Acceleration = (Vf - Vi)/t
Since Vf= 60m/s
Vi= 15m/s
T= 15s
=> a= (60m/s - 15m/s)/15s
= 3
So the acceleration is 3m/s^2

3 0

3 years ago

A 90 kg body is taken to a planet where the acceleration due to

Serggg [28]

Answer:

2250N

Explanation:

W= mg,

where W= weight

m= mass

g= acceleration due to gravity

Given that the body is 90kg, m= 90kg.

Acceleration due to gravity of planet

= 2.5(10)

= 25 m/s²

Weight of body on planet

= 90(25)

= 2250N

*Mass is the amount of matter an object has and is constant (same on earth and the planet).

6 0

3 years ago

Read 2 more answers

A sinusoidally oscillating current I ( t ) with an amplitude of 9.55 A and a frequency of 359 cycles per second is carried by a

UNO [17]

Answer:

$P_{avg} = 6.283*10^{-9} \ W$

Explanation:

Given that;

I₀ = 9.55 A

f = 359 cycles/s

b = 72.2 cm

c = 32.5 cm

a = 80.2 cm

Using the formula;

$\phi = \frac{\mu_o Ic }{2 \pi} In (\frac{b+a}{b})$

where;

$E= \frac{d \phi}{dt}$

$E = \frac{\mu_o}{2 \pi}c In (\frac{b+a}{a}) I_o \omega cos \omega t$

$E_{rms} = \frac { {\frac{\mu_o \ c}{2 \pi} In (\frac{b+a}{a}) I_o (2 \pi f)}}{\sqrt{2}}$

Replacing our values into above equation; we have:

$E_{rms} = \frac { {\frac{4 \pi*10^{-7}*0.325}{2 \pi} In (\frac{72.2+80.2}{80.2}) *9.55 (2 \pi *359)}}{\sqrt{2}}$

$E_{rms} = \frac {8.98909588*10^{-4} }{\sqrt{2}}$

$E_{rms} = 6.356*10^{-4} \ V$

Then the $P_{avg$ is calculated as:

$P_{avg} = \frac{E^2}{R}$

$P_{avg} = \frac{(6.356*10^{-4})^2}{64.3}$

$P_{avg} = 6.283*10^{-9} \ W$

6 0

4 years ago

You place your pencil on your desk it stays there

zepelin [54]

Answer:

yes

Explanation:

6 0

3 years ago

Read 2 more answers