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hram777 [196]
3 years ago
10

Will give Brianliest answer. help.

Physics
1 answer:
dimaraw [331]3 years ago
3 0

Answer:6.2

Explanation:

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A jet plane traveling 1890 km/h (525 m/s) pulls out of a dive by moving in an arc of radius 5.20 km. What is the plane's acceler
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Answer:

Acceleration of the plane, a = 5.4 g

Explanation:

It is given that,

Speed of the jet plane, v = 1890 km/h = 525 m/s

Radius of the arc, r = 5.20 km = 5200 m

The plane is moving in the circular path, the centripetal acceleration will act on it. It is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(525\ m/s)^2}{5200\ m}

a=53.004\ m/s^2

We know that, the value of g is, g=9.8\ m/s^2

\dfrac{a}{g}=\dfrac{53.004\ m/s^2}{9.8\ m/s^2}=5.4

a=5.4\times g

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