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valentina_108 [34]
3 years ago
6

One end of a metal rod is placed in a hot fire. At the atomic level, how does heat transfer down the length of the rod?

Physics
2 answers:
fiasKO [112]3 years ago
6 0

Answer:

Through the means of conduction

Explanation:

Sedaia [141]3 years ago
4 0
All metal atoms have mobile electrons, making them good conductors of heat. Heat is transferred as the free electons at the end that's being heated, rapidly move from atom to atom in the metallic bonds. This rapid movement of electrons allows for the transfer of heat energy from one end of the rod to the other.
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330 g of water at 55°c are poured into an 855 g aluminum container with an initial temperature of 10°
Olenka [21]
The final temperature of the system is 32.5°
we know,  H = mcT 
where, H = Heat content of the body 
m = Mass,
c = Specific heat
T = Change in temperature
According to to the Principle of Calorimetry 

The net heat remains constant i.e. 
⇒ the heat given by water = heat accepted by the aluminum container.
⇒ 330 x 1 x (45 - T) = 855 x \frac{900}{4200} x (T - 10) 

⇒ 14,850 - 330T = 183.21T  - 1832 

⇒ - 513.21 T = - 16682

or T = 32.5°
3 0
3 years ago
Neutrons are also known as____
PilotLPTM [1.2K]
C.alpha particles....
4 0
3 years ago
Read 2 more answers
It is known that the 10 kg pipe will roll up the ramp and not slide on the ramp when P becomes sufficiently large. Using the rol
riadik2000 [5.3K]

Answer:

65.73N

Explanation:

The frictional force is a force that opposes the motion of an object on a flat surface or an inclined surface.

It is always acting up an incline plane .

Since the pipe will tend to roll up the plane, then both the impending force P also known as frictional force and the moving force Fm both will be acting up the plane.

The net force acting up the plane is

Fnet = P + Fm... (1)

The force perpendicular to the plane known as the normal reaction R must be equal to the force acting along the ramp in other to keep the body in equilibrium i.e R = Fnet

If R = W = mgcos (theta)

and Fm = mgsin(theta)

Then mgcos theta = Fnet

mgcos (theta) = P+Fm

mgcos (theta) = P+mgsin(theta)

P = mgcos (theta) - mgsin(theta)... (2)

Given mass = 10kg

g = 9.81m/s

We can get theta from the formula;

µ = Ff/R = wsin theta/wcos theta

µ = sin theta/cos theta

µ = tan(theta)

0.3 = tan (theta)

theta = arctan0.3

theta = 16.7°

P = 10(9.81)cos16.7° - 10(9.81)sin16.7°

P = 98.1(cos16.7°-sin16.7°)

P = 98.1(0.67)

P = 65.73N

The minimum force P required to cause impending motion is 65.73N

5 0
3 years ago
What type of circuit is in the diagram? Group of answer choices:
eduard

Answer:

Series circuit

Explanation:

Because the electrical components are connected one after each other in a single loop, rather than alongside each other, forming extra loops.

8 0
3 years ago
Read 2 more answers
A mass of gas has a volume of 4 m3, a temperature of 290 K, and an absolute pressure of 475 kPa. When the gas is allowed to expa
umka2103 [35]

Answer : The correct option is, (B) 279.2 Kpa

Solution : Given,

Initial pressure of gas = 475 Kpa

Initial volume of gas = 4m^3

Final volume of gas = 6.5m^3

Initial temperature of gas = 290 K

Final temperature of gas = 277 K

Using ideal gas equation :

Formula used :

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas

P_2 = final pressure of gas

V_1 = initial volume of gas

V_2 = final volume of gas

T_1 = initial temperature of gas

T_2 = final temperature of gas

Now put all the given values in the above formula, we get the final pressure of the gas.

\frac{(475Kpa)\times (4m^3)}{290K}=\frac{P_2\times (6.5m^3)}{277K}

P_2=279.2Kpa

Therefore, the absolute pressure of the gas after expansion is, 279.2 Kpa

5 0
2 years ago
Read 2 more answers
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