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valentina_108 [34]
3 years ago
6

One end of a metal rod is placed in a hot fire. At the atomic level, how does heat transfer down the length of the rod?

Physics
2 answers:
fiasKO [112]3 years ago
6 0

Answer:

Through the means of conduction

Explanation:

Sedaia [141]3 years ago
4 0
All metal atoms have mobile electrons, making them good conductors of heat. Heat is transferred as the free electons at the end that's being heated, rapidly move from atom to atom in the metallic bonds. This rapid movement of electrons allows for the transfer of heat energy from one end of the rod to the other.
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A 40 kg boy is moving upwards upwards in a lift with an acceleration of 2 m /s ^2 what would be the weight felt by him if measuu
neonofarm [45]

Answer:

<h2> 48kg</h2>

f = ma \\

w \:  =  \frac{f}{g}  \\

Explanation:

f \:  = ma \\ f - mg = ma \\ f = ma + mg \\ f = 40 \times 2 + 40 \times 10 \\ f = 480

w =  \frac{f}{g}  \\w =   \frac{480}{10}  \\ w = 48kg

5 0
3 years ago
Power plants can be powered by fossil fuels, such as coal or natural gas, or nuclear power to produce steam to turn turbines to
Naddika [18.5K]
<span>Nuclear energy is cleaner while generating electricity. Nuclear fission provides energy without releasing greenhouse gases such as carbon dioxide. However, nuclear power plants generate significant amounts of radioactive waste.  That is why we should not choose nuclear energy over fossil fuel power plants.</span>
7 0
3 years ago
Two loudspeakers are 1.60 m apart. A person stands 3.00 m from one speaker and 3.50 m from the other. (a) What is the lowest fre
VMariaS [17]

Answer:

Explanation:

Given

Distance between two loud speakers d=1.6\ m

Distance of person from one speaker x_1=3\ m

Distance of person from second speaker x_2=3.5\ m

Path difference between the waves is given by

x_2-x_1=(2m+1)\cdot \frac{\lambda }{2}

for destructive interference m=0 I.e.

x_2-x_1=\frac{\lambda }{2}

3.5-3=\frac{\lambda }{2}

\lambda =0.5\times 2

\lambda =1\ m

frequency is given by

f=\frac{v}{\lambda }

where v=velocity\ of\ sound\ (v=343\ m/s)

f=\frac{343}{1}=343\ Hz

For next frequency which will cause destructive interference is

i.e. m=1 and m=2

3.5-3=\frac{2\cdot 1+1}{2}\cdot \lambda

\lambda =\frac{1}{3}\ m

frequency corresponding to this is

f_2=\frac{343}{\frac{1}{3}}=1029\ Hz

for m=2

3.5-3=\frac{5}{2}\cdot \lambda

\lambda =\frac{1}{5}\ m

Frequency corresponding to this wavelength

f_3=\frac{343}{\frac{1}{5}}

f_3=1715\ Hz                        

8 0
3 years ago
Need help quick!!!!
BARSIC [14]
The answer is B. Unbalanced force
3 0
3 years ago
Read 2 more answers
When the mirror is rotated, the normal will turn as well, but will the incident Ray and reflected ray turn?
Inessa [10]

When a mirror is rotated . . .

-- The incident ray doesn't turn.  It's just the line from the source to the mirror. 
It would be there, in the same place, even if there was no mirror.

-- The normal turns.  It's the line perpendicular to the mirror, so it must turn
with the mirror.

-- Since the normal tuns and the incident ray doesn't, the angle between them
must change.  And since the angle of the reflected ray is equal to the angle of
the incident ray, the reflected ray must also turn.


6 0
3 years ago
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