Price of movie ticket in Japan is x=7.362$
Price of movie ticket in Switzerland is y=13.652$
Step-by-step explanation:
Let, Price of movie ticket in Japan is x
Price of movie ticket in Switzerland is y
Statement 1 : Total of 79.39$ of three movie ticket in Japan and two movie ticket in Switzerland
We write, 3x+2y=79.39 ( Equation 1 )
Statement 1 : Total of 75.68$ of two movie ticket in Japan and three movie ticket in Switzerland
We write, 2x+3y=75.68 ( Equation 2 )
Solving by method of elimination
Multiplying equation 1 by 2, we get
6x+4y=158.78
Multiplying equation 2 by 3, we get
6x+9y=227.04
Subtracting both the linear equation,
6x+4y=158.78
- 6x+9y=227.04
_______________
0x-5y=(158.78-227.04)
-5y=(-68.26)
5y=68.26
y=13.652$
Replacing value of y in any equation
3x+2y=79.39
3x+2(13.652 )=79.39
x=17.362$
Thus,
Price of movie ticket in Japan is x=7.362$
Price of movie ticket in Switzerland is y=13.652$
Given width is 24 less than length.
W=L-24
Perimeter = 2(W+L)=2(L-24+L)=4L-48
But we're also given perimeter = 172'
Therefore 4L-48=172
solve for L
4L=172+48=220
L=55'
W=55-24 = 31'
Check: Perimeter = 2(W+L)=2(31+55)=2*86=172' good!
Answer: The dimensions of the garden are 31' * 55'
27,16,8,5,19,14,22,31,13,5,23,16,8 what is the mean and meidean and Interquartile range:
Olenka [21]
Median=16
Mean=15.9
Q1=8
Q2=22.5
Answer:
Step-by-step explanation:
<u>Given expression:</u>
<u>Find its value when x = 4 and y = 1, substitute:</u>
- 3(4 + 1) + 2*4² + (1 + 1)² =
- 3*5 + 2*16 + 2² =
- 15 + 32 + 4 =
- 51