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3 years ago

Carlos is making some observations from the roof of a building. Which angle is the angle of depression from Carlos to the car?

1 answer:

6 0

The figure that accompanies the question shows Carlos at point K on the roof of the building, the line KL as the horizontal line, and the car at point I on the street, on the horizontal line HPIJ. The depression angle is the angle below the horizontal line passing through Carlos (KL) and the line from Carlos to the Car (KI). So the vertices that define the depression angle are LKI and the depression angle requested is named LKI. Answer: angle LKI.

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when asked to write a point slope equation for a line passing through the points (-3,-5) and (2,4) a student wrote y-4=-9/5(x-2)

Eduardwww [97]

(-3,-5)(2,4)
slope(m) = (4 - (-5) / (2 - (-3) = (4 + 5) / (2 + 3) = 9/5

y - y1 = m(x - x1)
slope(m) = 9/5
(2,4)...x1 = 2 and y1 = 4
sub
y - 4 = 9/5(x - 1)....this is the correct answer

the student figured the slope wrong....it is 9/5...not -9/5

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2 years ago

1/2 to exponent of 4

Neporo4naja [7]

Answer:

0.0625 is the answer.

Hope it helps you!!!

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2 years ago

One exterior angle of a regular polygon measures 97°. What is the measure of one interior angle?

3241004551 [841]

Hello :) = Merhaba :)

Answer:

Step-by-step explanation:

The total angle of a polygon and its external angle must be 180°.

So the inner angle of this polygon:

180 - 97 = 83° would.

NOTE: I'm not American. I'm just a Turk who wants to help you. So if my sentences are wrong, please forgive me.

#Cevapistevereyim

Başarılar :) = Achievements :)

4 0

3 years ago

Alex purchased a new car for $28,000. The car's value depreciates 7.25% each year. What will be the value of the car 5 years aft

Anestetic [448]

A = 28000(0.9275)^5

a = 19219

$19,219 is the answer

Hoped this helped

8 0

2 years ago

You work in a chemical lab. Last quarter, you successfully completed an average of about 5 chemical analyses per day. This quart

Kryger [21]

Answer: 60%

Step-by-step explanation:

Since, According to the question, Last quarter, we successfully completed an average of about 5 chemical analyses per day.

Therefore initially our average = 5 chemical analyses per day.

Again, From the question, This quarter, we have increased this average to about 8 per day.

Therefore New average =chemical analyses 8 per day

Thus, Percentage change in the average = (Initial average - New average)×100/ initial average

= $\frac{8-5}{5} \times 100$

= $\frac{3}{5} \times 100$

= 60 %

Therefore, Percentage change in the average=60 %

7 0

2 years ago

Read 2 more answers