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Stels [109]
3 years ago
13

A jar of mayonnaise is shaped like a cylinder. The radius of the jar is 1.5 in. and its height is 7 in. The mayonnaise sells for

$0.08 per in³.
What is the cost of the jar of mayonnaise?

Use 3.14 to approximate pi.

Round your answer to the nearest penny.

Enter your answer in the box.
Mathematics
2 answers:
tresset_1 [31]3 years ago
7 0
The answer is $3.96

I hope this helped. :)
Hitman42 [59]3 years ago
3 0
I think the answer is 3.96
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-3+3x=-2(x+1)<br> the 2 is a negative<br> please break it down
Veronika [31]
-3+3x=-2(x+1) First: I will get rid of the bracket:


-3+3x=-2x-2

Now, all the x goes to the left side, all the numbers without x to the right side:


3x+2x=-2+3

we add up"

5x=1

divide by 5:

x= \frac{1}{5}

7 0
3 years ago
Read 2 more answers
Which statement is true about the ratios of squares to<br> cicles in the tables? PLS HURRY!!!!
notka56 [123]

Answer:

show us a screenshot or image

or type it out, copy paste

Step-by-step explanation:

8 0
2 years ago
Find the integral using substitution or a formula.
Nadusha1986 [10]
\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
\rm (x^2+2x+5)'=2x+2

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx

and then split the fraction,

\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx

Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

So the first integral changes,

\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx

integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

So we have this going on,

\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du

simplying a lil bit,

\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du

and hopefully from this point you recognize your arctangent integral,

\rm ln|x^2+2x+5|+\frac52arctan(u)

undo your substitution as a final step,
and include a constant of integration,

\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c

Hope that helps!
Lemme know if any steps were too confusing.

8 0
3 years ago
Need help with these math questions
PSYCHO15rus [73]

\sqrt{16-x}        x = 8

Since x = 8, you can plug in/substitute 8 for "x" in the equation:

\sqrt{16-x}

\sqrt{16-8}

\sqrt{8}

2.82842

2.83 You answer is the 4th option


\sqrt{x+7}     x = 9

Plug in 9 for "x" in the equation

\sqrt{x+7}

\sqrt{9+7}

\sqrt{16}

4    Your answer is the 1st option

4 0
3 years ago
||BRAINLIEST 20 POINTS!||
Ipatiy [6.2K]

Answer:

-3+1/5

Step-by-step explanation:

4 0
2 years ago
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