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Ivahew [28]
3 years ago
11

the length and width of a rectangle lot are in the ratio 3 to 2. if he perimeter of the lot is 530yards, find the length and wid

th
Mathematics
1 answer:
sergey [27]3 years ago
3 0
Length = l = 3x
Width = w = 2x
P = 2l + 2w
P = 2(3x) + 2(2x)
530 = 6x + 4x
530 = 10x
53 = x
Length = 3x = 3(53) = 318 / 2 sides = 159
<span>Width = 2x = 2(53) = 212/ 2 sides = 106

the length of the lot is 159 yards
the width of the lot is 106 yards</span>
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Hey. Let me help you on this one.

In order for us to solve this problem easier, let's break it apart. We can also graph the triangle so we get visual of this problem.

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Let's form a SOHCAHTOA function which you have probably already learned in your Geometry course.

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