False, There are no genetics that can save you from constant overeating and there are no genetics that can prevent you from working out, at least to your possible extent.
<h2>( a ) 36 J ( b ) 15.75 J</h2>
Explanation:
In this case a body of 18 kg is placed on the smooth surface .
The distance covered covered by the body in four seconds can be found by the relation S = u t + 1/2 a t²
Here S is the displacement , u is the initial velocity and a is the acceleration of the body . t is the time taken
In this case initial velocity u = 0 , because the body is at rest .
the acceleration is force/mass = 9/18 = 0.5 m/sec²
The values are substituted in the above equation
Thus S = 0 + 1/2 x 0.5 x ( 4 )² = 4 m
Therefore the body will move 4 m in four seconds
The work done = Force x displacement
= 9 x 4 = 36 J
The displacement in fourth second can be found by relation
S₄ = u + a/2 ( 2 n - 1 ) ; where n is the number of seconds , which is 4 in this case
Thus S₄ = 0 + 0.5/2 ( 2 x 4 - 1 ) = 3.5/2 = 1.75 m
Therefore the work done = 9 x 1.75 = 15.75 J
Answer:
the rates of rock formation are similar. i could be wrong tho.....
Explanation:
Answer:
The answer is i just need the 5 pt sowwry bro hope you have luck finding it ;]
Explanation:
you prolly alr found it but it doesnt really matter
Answer:
Explanation:
There are a couple of different ways in which you can solve this and still get the same answer rounded. Since we are talking about KE, I will show you the way that utilizes KE and PE to get the total energy and then figure from that how high the object can go. First off, I'm going to use a mass of 1.0 kg for 2 significant digits. The total energy of a system is found in the equation
TE = PE + KE that says the total energy available to a system is equal to its kinetic energy plus its potential energy. Right off, we are given the KE value of 100 (Even though it's not accurate, I'm going to say that that number has 3 sig fig's, just because rounding to 1 sig fig is counterproductive). If the KE is 100, then
TE = 100 + 0 (the PE is 0 if the object is not moving, which it's not if someone is holding it and then throws it upwards). That's the total amount of energy available to that system and it cannot go up and it cannot go down, it can only change form. If the TE = 100, then we move on to the second part of the problemwhich is finding out how high i can go. The max height of the object indicates that the KE is 0 (the object at its max height isn't moving, even though it's only not moving for a nanosecond. If the object is not moving AND it's at its highest point, KE is 0 and PE is at a max). That means that at this max height,
TE = 0 + PE and filling in the value for TE:
100 = PE and PE = mgh where m is mass, g is the pull of gravity, and h is the height (our unknown).
100 = (1.0)(9.8)(h) and
so, to 2 sig fig's,
h = 1.0 × 10¹ meters (or 10 meters)