Question

An object slides down a frictionless inclined plane. At the bottom, it has a speed of 9.80 m/s. What is the vertical height of the plane

Answer 1

The vertical height of the given plane is 4.9 m.

The given parameters:

• speed of the object at the bottom of the ramp, v = 9.8 m/s

The vertical height of the plane is calculated by applying principle of conservation of mechanical energy as follows;

$P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{9.8 \times 9.8}{2 \times 9.8} \\\\h = 4.9 \ m$

Thus, the vertical height of the given plane is 4.9 m.

Learn more about conservation of mechanical energy here: brainly.com/question/332163