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koban [17]
3 years ago
15

How is velocity ratio of wheel and axle calculated​

Physics
1 answer:
Rudiy273 years ago
7 0

Answer:

VR = \frac{Radius of the wheel}{Radius of the axle}

Explanation:

Velocity ratio (VR) of a machine is a term that compares the distance moved by effort put into the machine to the distance moved by the load.

A wheel and axle is a device for lifting of a load through a height. It is made up of two circular parts called wheel and axle. Its velocity ratio (VR) can be determined by:

VR = \frac{Radius of the wheel}{Radius of the axle}

For a practical wheel and axle, the diameter of the wheel is greater than the diameter of the axle.

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<span>Rayed craters-</span><span> were the last features to form on the moon.</span>
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An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.245 T. If the kinetic energy of the electr
Amiraneli [1.4K]

Answer

Given,

Magnetic field, B = 0.245 T

KE of the electron = 2.90 x 10⁻¹⁹ J

Speed of electron = ?

KE = \dfrac{mv^2}{2}

v=\sqrt{\dfrac{2(KE)}{m}}

v=\sqrt{\dfrac{2\times 2.90\times 10^{-19}}{9.11\times 10^{-31}}}

v = 7.97 x 10⁵ m/s

radius of the circular path

so,

\dfrac{mv^2}{r}=evB

r=\dfrac{mv}{eB}

r=\dfrac{9.11\times 10^{-31}\times 7.97 \times 10^5}{1.6\times 10^{-19}\times 0.245}

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8 0
3 years ago
A Net Force Of 60 N Accelerates A 4-kg Mass Over A Distance Of 10 M.
storchak [24]
Net Force = 600 N
Kinetic Energy = 600 J
(Work done) >> KE since there is no mention of frictional forces
5 0
3 years ago
Exercise 1 - Questions 1. Hold the grating several inches from your face, at an angle. Look at the grating that you will be usin
choli [55]

Answer:

1) on the surface you can see the slits with equal spacing, on the one hand and on the other hand it is smooth.

2)If the angle is zero we see a bright light called undispersed light

For different angles we see the colors of the spectrum

3) must be able to see the well-collimated light emission source

Explanation:

1) A diffraction grating (diffraction grating) is a surface on which a series of indentations are drawn evenly spaced.

These crevices or lines are formed by copying a standard metal net when the plastic is melted and after hardening is carefully removed, or if the nets used are a copy of the master net.

The network can be of two types of transmission or reflection, in teaching work the most common is the transmission network, on the surface you can see the slits with equal spacing, on the one hand and on the other hand it is smooth.

The number of lines per linear mm determines which range of the spectrum a common value can be observed to observe the range of viable light is 600 and 1200 lines per mm.

2) when looking through the diffraction grating what we can observe depends on the relative angle between the eye and the normal to the network.

If the angle is zero we see a bright light called undispersed light

For different angles we see the colors of the spectrum, if it is an incandescent lamp we see a continuum with all the colors in the visible range and if it is a gas lamp we see the characteristic emission lines of the gas.

3) Before mounting the grid on the spectrometer, we must be able to see the well-collimated light emission source, this means that it is clearly observed.

The spectrometers have several screws to be able to see the lamp clearly, this is of fundamental importance in optical experiments.

3 0
4 years ago
8. Object A has a momentum of 80 Ns and collides and sticks to object B which has a momentum of -30 Ns. What is the momentum of
BigorU [14]

Given,

The momentum of the object A before the collision, p₁ =80 Ns

The momentum of the object B before the collision, p₂=-30 Ns

Given that the objects stick together after the collision.

From the law of conservation of momentum, the total momentum of a system should always remain the same. Thus the total momentum of the objects before the collision must be equal to the total momentum of the objects after the collision.

Thus,

p_1+p_2=p

Where p is the total momentum of the system at any instant of time.

On substituting the known values,

\begin{gathered} p=80-30 \\ =50\text{ Ns} \end{gathered}

Therefore the total momentum of the system is 50 Ns

Thus the momentum of the object AB after the collision is 50 Ns

6 0
1 year ago
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