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Sergio [31]
3 years ago
5

What would happen to an object if the force of gravity on Erath decreased by half

Chemistry
1 answer:
abruzzese [7]3 years ago
6 0

Answer:

the object will float for a few seconds and most likely fall back down because it still has a little bit of gravity attached or it would float a few inches up but not too high in the air where its out of reach

Explanation:

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An individual is hospitalized and the initial blood work indicates high levels of hco3- in the blood and a ph of 7. 47. This wou
expeople1 [14]

An individual is hospitalized and the initial blood work indicates high levels of HCO_{3} ^{-} in the blood and a pH of 7. 47. This would indicate the individual probably has compensated respiratory acidosis.

A chronic illness usually leads to compensated respiratory acidosis because the kidneys have time to adjust to the delayed onset. Even if the PCO_{2} is elevated in a compensated respiratory acidosis, the pH is within the usual range.

The kidneys counteract a respiratory acidosis by increasing the amount of HCO_{3} that tubular cells reabsorb from the tubular fluid, the amount of H^{+} that collecting duct cells secrete while also producing HCO_{3} , and the amount of NH_{3} buffer that is formed through ammoniagenesis.

Respiratory acidosis is frequently brought on by hypoventilation as a result of: breathing depression , paralysis of the respiratory muscles, diseases of the chest wall , abnormalities of the lung parenchyma and abdominal squeezing.

Learn more about Respiratory acidosis here;

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5 0
1 year ago
A intramuscular medication is given at 5.00mg/kg of body weight. What is the dose in grams for a 180-lb patient?
Alex17521 [72]
0.408 gram for 180-lb patient
7 0
4 years ago
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Please, can i get some help with these question? Can anyone please answer what exactly i should write?
pav-90 [236]
Use photomath. I would really recommend it! Hope this helps!
8 0
3 years ago
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Help in chem please!!!!!!
IgorLugansk [536]

This is a one-step unit analysis problem.  Since we are staying in moles, grams of our compound, and thus molar mass, is not needed.

1 mole is equal to 6.022x10²³ particles as given, so:

1.5x10^{24} particles FeO_{2} (\frac{1mol}{6.022x10^{23}particles } )=2.49 molFeO_{2}

<h3>Answer:</h3>

2.49 mol

Let me know if you have any questions.

3 0
3 years ago
A 47.0 mL aliquot of a 0.400 M stock solution must be diluted to 0.100 M. Assuming the volumes are additive, how much water shou
mel-nik [20]

Answer:

The answer is 0.188L

Explanation:

I did the problem on paper and put the answer on the pictures. I'm sorry if I didn't explain it well but I hope I helped.

5 0
3 years ago
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