Question

Two similar gold spheres both have a charge of q. The centers of the

Answer 1

Answer:

A.One q would be doubled and r would remain the same.

Explanation:

As we know by Coulomb's law of electrostatic force is given as

$F = \frac{kq_1q_2}{r^2}$

As we know that the distance between the two charges is given as r

and the two charges are given as q1 and q2

so from above equation we can say that if we double either of the charge then the electrostatic force will double

so we have

$F' = \frac{k(2q_1)(q_2)}{r^2}$

so we have

$F' = 2F$

So correct answer will be

A.One q would be doubled and r would remain the same.