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1 year ago

Which types of questions can most likely be answered through a scientific investigation?

1 answer:

4 0

Subjective questions can be answered most likely through well-designed scientific investigations. Investigating peoples opinions or favorites does not involve any scientific investigations.

<h3>What are scientific investigation?</h3>

Scientific investigations include study on different natural phenomenon through well designed research methodologies. They include a preliminary hypothesis based on observations and various scientific records helps for reference.

Through well designed scientific experiments we can solve subjective questions and can be helpful in solving different environmental or social issues.

Peoples opinion or objective types questions are not targeted at scientific investigation, hence, option b is correct.

To find more on scientific investigations, refer here:

brainly.com/question/8386821

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Three point charges are arranged along the x axis. Charge q1=-4.00nC is located at x= .250 m and q2= 2.40 nC is at the x= -.300m

Umnica [9.8K]

Answer:

q₃=5.3nC

Explanation:

First, we have to calculate the force exerted by the charges q₁ and q₂. To do this, we use the Coulomb's Law:

$F= k\frac{|q_aq_b|}{r^{2} } \\\\\\F_{13}=(9*10^{9} Nm^{2} /C^{2} )\frac{|(-4.00*10^{-9}C)q_3|}{(.250m)^{2} } =576q_3N/C\\\\F_{23}=(9*10^{9} Nm^{2} /C^{2} )\frac{|(2.40*10^{-9}C)q_3|}{(.300m)^{2} } =240q_3N/C\\$

Since we know the net force, we can use this to calculate q₃. As q₁ is at the right side of q₃ and q₁ and q₃ have opposite signs, the force F₁₃ points to the right. In a similar way, as q₂ is at the left side of q₃, and q₂ and q₃ have equal signs, the force F₂₃ points to the right. That means that the resultant net force is the sum of these two forces:

$F_{Net}=F_{13}+F_{23}\\\\4.40*10^{-9} N=576q_3N/C+240q_3N/C\\\\4.40*10^{-6} N=816q_3N/C\\\\\implies q_3=5.3*10^{-9}C=5.3nC$

In words, the value of q₃ must be 5.3nC.

7 0

3 years ago

A block with mass 0.5kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.2m. whe

dangina [55]

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
Read more on Brainly.com - brainly.com/question/1581851#readmore

4 0

3 years ago

If a crane worker lifts a crate with a mass of 250 kg from the ground to a

mina [271]

The gravitational of a body is possessed by the body due to the virtue of its position.

The formula for gravitational potential energy is,

P.E = mgh joules

Substituting the values

196*9.8*250= 49k

7 0

2 years ago

It would take almost 2 years for the fastest human-made spacecraft to travel from earth to europa. about how long would it take

worty [1.4K]

First, we need the distance of Europe and Wolf-359 from Earth.
- The distance of Europe from Earth is: $d_E = 6.28 \cdot 10^8 km$
- The distance of Wolf-359 from Earth is instead 7.795 light years. However, we need to convert this number into km. 1 light year is the distance covered by the light in 1 year. Keeping in mind that the speed of light is $c=3 \cdot 10^8 m/s$ , and that in 1 year there are
365 days x 24 hours x 60 minutes x 60 seconds = $3.154 \cdot 10^7 s/y$ , the distance between Wolf-359 and Earth is
$d_W = 7.995 ly\cdot3\cdot 10^8 m/s \cdot 3.154 \cdot 10^7 s=7.38 \cdot 10^{16}m=7.38 \cdot 10^{13}km$

Now we can calculate the time the spaceship needs to go to Wolf-359, by writing a simple proportion. In fact, we know that the spaceship takes 2 years to cover $d_E$ , so
$2 y:d_E = x:d_W$
from which we find $x$ , the time needed to reach Wolf-359:
$x= \frac{2 y\cdot d_W}{d_E}=2.35 \cdot 10^5 years$

4 0

3 years ago

An object is place 30.5 cm from a convex lens that has a focal length of 8.0cm.where is the image ?

77julia77 [94]

Answer:

Image is between F and 2F. And the exact location is:

q = 10.84 cm

Explanation:

The convex lens form different kinds of images with different sizes and locations, for the different positions of an object. In this case, the object is placed 30.5 cm from the convex lens with a focal length of 8 cm. This means that it is the case of the object placed beyond 2F. In this case, the image formed has the following characteristics:

1. Image is real.

2. Image is inverted

3. Image is diminished

<u>4. Image is located between F and 2F</u>

For exact location we use the thin lens formula:

$\frac{1}{f} = \frac{1}{p} + \frac{1}{q}$

where,

f = focal length = 8 cm

p = object distance = 30.5 cm

q = image distance = ?

Therefore,

$\frac{1}{8\ cm} = \frac{1}{30.5\ cm} + \frac{1}{q} \\\frac{1}{8\ cm} - \frac{1}{30.5\ cm} = \frac{1}{q}$

7 0

2 years ago