1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marysya [2.9K]
3 years ago
14

Which changes can reach dynamic equilibrium

Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
5 0

Answer:

D - chemical and physical

Explanation:

Only chemical and physical changes can reach the level of dynamic equilibrium. Nuclear reactions cannot reach dynamic equilibrium.

  • A system is in dynamic equilibrium when the rate of forward reaction is the same as that of backward reaction in a reversible reaction.
  • Nuclear reactions cannot be reversed.
  • Dynamic equilibrium is prominent in chemical reactions. It is commonly found that as a reaction occurs, the backward and forward reactions can reach equilibrium levels.
  • In physical changes, this can also occur when certain conditions of pressure and temperatures are satisfied.
You might be interested in
Does beryllium (Be) or Sodium (Na) have the same electron arrangement as Magnesium (Mg)? Why?
Finger [1]

Answer:

Na has the most similar configuration.

Explanation:

Na electron configuration: 1s²2s²2p⁶3s¹ or [Ne] 3s₁

Mg electron configuration: 1s²2s²2p⁶3s² or [Ne] 3s²

Be electron configuration: 1s²2s² or [He] 2s²

This is because Na and Mg are right next to each other in the same period (horizontal).

3 0
3 years ago
The wavelength of a light wave can be used to measure which of the following
Tema [17]
Wavelength is the distance between crests of the wave.
4 0
3 years ago
Two protons and two neutrons are released as a result of this reaction.
Murljashka [212]

<u>Answer:</u> The particle released in the given reaction is one alpha particle

<u>Explanation:</u>

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given fission reaction:

^{222}_{86}\textrm{Rn}\rightarrow ^A_Z\textrm{X}+^{218}_{84}\textrm{Po}

  • <u>To calculate A:</u>

Total mass on reactant side = total mass on product side

222 = A + 218

A = 4

  • <u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

86 = Z + 84

Z = 2

The isotopic symbol of unknown element is _{2}^{4}\textrm{He}. Another name of helium atom is alpha particle.

Hence, the particle released in the given reaction is one alpha particle

3 0
3 years ago
Read 2 more answers
Which shell is the outermost for oxygen?<br> A 192<br> B. 292<br> C. 252P<br> D. 2P
nadya68 [22]
Typical day of a new day in my house with my phone in my car so I’m not going hard I don’t know how much it was
4 0
3 years ago
5 A Punnett square is shown below. The domin
arsen [322]
The answer is 25 percent
7 0
3 years ago
Read 2 more answers
Other questions:
  • Convert 3.82 inches to km
    8·2 answers
  • An experimenter found that for the hydrolysis of lactose, ΔH° = +0.44 kJ mol–1 and ΔS° = +0.031 kJ mol–1 K–1. ΔG°for this reacti
    8·1 answer
  • Which of these acids occurs naturally in the body and performs regularly functions?
    7·1 answer
  • Iron(II) chloride and sodium carbonate react to make iron(II) carbonate and sodium chloride: FeCl2(aq) + Na2CO3(s) → FeCO3(s) +
    15·2 answers
  • In the reaction Na2CO3 + 2HCl → 2NaCl + CO2 + H2O, how many grams of CO2 are produced when 7.5 moles of HCl is fully reacted?
    6·2 answers
  • Purification of chromium can be achieved by electrorefining chromium from an impure chromium anode onto a pure chromium cathode
    14·1 answer
  • Why are lead compounds harmful to us?
    7·1 answer
  • Fill in the coefficient needed to make the equation balanced.
    11·1 answer
  • How many moles are in 12 grams of NH3?​
    11·1 answer
  • [please answer fast!] If the hydroxide ion concentration is 2x10^-3 M, what is the pH of the solution? Show your working.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!