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nexus9112 [7]
3 years ago
12

Name one trend observable in a periodic table

Chemistry
2 answers:
trasher [3.6K]3 years ago
8 0
Electronegativity
Ionization energy
Electron affinity
Atomic radius
Melting point
wolverine [178]3 years ago
8 0

Answer:

Major periodic trends include: electronegativity, ionization energy, electron affinity, atomic radius, melting point, and metallic character.

Explanation:

These six are the major trends.

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What data must you know about the isotopes of an element to calculate the atomic mass of the element?
pashok25 [27]
The relative abundance and the mass number usually they give these to you. They give me both these values in my chemistry class so i just multiply add the products and get my answer
3 0
3 years ago
What is the pH of a solution that contains 0.003 M HBr?*<br> O 1.0<br> O 2.5<br> O 5.8<br> O 11.5
maxonik [38]

Answer:

pH = 2.5

Explanation:

Given data:

Concentration of HBr = 0.003 M

pH of solution = ?

Solution:

Formula:

pH = -log[H⁺]

by putting values,

pH = -log [ 0.003]

pH = 2.5

5 0
3 years ago
A gas has a volume of 62.65 L at STP. At what temperature (in oC) would the volume of the gas be 78.31 L at a pressure of 612.0
masha68 [24]

Answer:

1.788 C DEGREES

Explanation:

STP is 1 atm at  273.15 K

P1V1/T1  = P2V2/T2

(1)(62.65) / (273.15) = (612/760)(78.31)/T2

T2 = 274.93 K     = 1.788 C

5 0
2 years ago
The refining of aluminum from bauxite ore (which contains 50.% Al2O3 by mass) proceeds by the overall reaction 2Al2O3 + 3C → 4Al
iragen [17]

Answer:

18.9 x 10¹³ grams of Bauxite Ore

Explanation:

Al₂O₃ = 50% of Bauxite Ore

Al₂O₃ = 0.5 (Bauxite Ore)--------------------------------------- (1)

Overall reaction:

2Al₂O₃ + 3C → 4Al + 3CO₂--------------------------------------- (2)

[ Al= 27 , O=16, C=12]

From  (2), 2 moles of  Aluminium oxide (Al₂O₃) gives  4 moles of Aluminium

In terms of grams, we can say:

Al₂O₃ = [2(27) +3(16)]

         = 54 +48

         =102grams

2 moles of Al₂O₃ = 2 x102grams

                            =204grams

4 moles of Al = 4 x 27

                      =108 grams

So from (2):

204 grams of  Al₂O₃   = 108 grams of  Aluminium

x grams of  Al₂O₃        =  5.0 x 10¹³grams of Aluminium

Calculating for x:

x =  (204 x  5.0 x 10¹³)/ 108

  = 9.44 x 10¹³ grams

So 9.44 x 10¹³ grams of pure bauxite (Bauxite) is required.

However the to calculate the quantity of raw bauxite, we use (1):

Bauxite ore = Pure Bauxite/0.5

                   =   9.44 x 10¹³ grams/0.5

                   =   18.88 x 10¹³ grams

                    ≈ 18.9 x 10¹³ grams

 

8 0
3 years ago
Rank the following elements by electron affinity 1) fluorine 2) selenium 3) arsenic 4) potassum 5) argon
denis23 [38]

Answer:

Fluorine > Selenium > Arsenic > Potassium > Argon

Explanation:

Electron affinity describes the ability or readiness or tendency of an atom to gain an electron.

The higher the value, the higher the tendency. Electron affinity depends on the on the nuclear charge and atomic radius. When nuclear charge is more, electron affinity is high, when atomic radius increases electron affinity reduces.

Noble gases such as Helium, Neon, and Argon would have 0 affinity for electrons because of their stable electronic configuration. From the list, Ar is the least in terms of electron affinity.

Potassium is a metal with large electropositivity which describes the tendency of an atom to lose electrons. Potassium would readily lose electrons instead of gaining.

Between Arsenic and Selenium: Arsenic belongs to group V and Selenium group VI. The two elements both belong to period IV on the periodic table. Across a period, electron affinity increases due to increase in nuclear charge. Therefore, Selenium would have a greater electron affinity compared to Arsenic.

Fluorine has the highest electron affinity of all. It needs just an electron to complete its octet.

7 0
3 years ago
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