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zvonat [6]
3 years ago
5

Two rods are made from materials that have different Young's moduli. The rods are constructed to have the same length and same c

ross-sectional area. The same forces pull similarly on each rod. The rod with the larger Young's modulus will stretch more than the rod with the smaller Young's modulus.
A. True
B. False
Physics
1 answer:
stiv31 [10]3 years ago
8 0

Answer:

False

Explanation:

Let the Young's modulus of two different material is Y and Y'

Let F is the force applied, L is the initial length and A is the area of crossection.

By the formula of Young's modulus

Y = \frac{F\times L}{A\times \Delta L}

Increase in length is inversely proportional to the Young's modulus, so more is the value of Young's modulus lesser be the extension in the length of rod.

Thus, the given statement is false.  

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Answer:

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3 years ago
Which one of the following is correct option: hydrogen,
Vinil7 [7]

Answer:

hydrogen

Explanation:

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In chemistry, it literally means power of hydrogen ions and it is a measure of the molar concentration of hydrogen ions in a particular solution, thus specifying the acidity, neutrality or basicity of chemical solutions.

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Hence, a solution with a pH of 7 is neutral.

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3 0
3 years ago
A projectile is launched with an initial velocity of 25 m/s at an angle of 30° above the horizontal. The projectile reaches maxi
Alchen [17]

Answer:

x ≈ 56 m

Explanation:

vertical initial velocity =v_{0y}(t) = 25 m/s* sin(30°)= 12.5 m/s

height = h

h =v_{0y}t+\frac{at^{2}}{2} \\\\65m = 12.5m/s*t + \frac{9.8m/s^{2}*t^{2}}{2} \\\\t=2.584 s

t- time is found solving quadratic equation.

horizontal velocity = v_{0x}=25m/s*cos(30^{o})=21.65 m/s

Horizontal velocity is constant, so distance x=v_{0x}*t =21.65 m/s *2.584 s=55.9 = 56 m

6 0
3 years ago
What is the direction of the force of an object moving in a circle?
Ivanshal [37]

Answer:

The answer is 45 degree angle

7 0
3 years ago
uppose a wheel is initially rotating at 10.0 rad/s while undergoing constant angular acceleration reaching a speed of 30.0 rad/s
Paul [167]

Answer:

t = 22.2 s

Explanation:

angular distance covered in the 36.0 s is

θ = ω(avg)t = ½(10.0 + 30.0)36 = 720 radians

720/2 = 360 radians

α = Δω/t = (30 - 10)/36 = 5/9 rad/s²

θ = ω₀t + ½αt²

360 = 10.0t + ½(5/9)t²

   0 = (5/18)t² + 10.0t - 360

   0 = t² + 36t - 1296

t = (-36 ±√(36² - 4(1)(-1296))) / 2

t = (-36 ±√(6480)) / 2

t = -18 ±√1620

we ignore the negative time result as it occurs before we care.

t = -18 + √1620 = 22.249223... s

8 0
3 years ago
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