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3 years ago

Why do you think fixed boundaries ""flip"" waves and loose boundaries do not?

Physics

1 answer:

Vinil7 [7]3 years ago

5 0

Answer:

When the obstacle is fixed, the law of action and reaction, makes the reflected wave is inverted.

When the obstacle is mobile, he mobile point, it moves in the direction of the wave, therefore there is no inversion of it.

Explanation:

Waves when they reach an obstacle behave like a shock, therefore if we use the conservation of momentum the wave must reverse its speed, this explains that the speed changes sign, the wave is reflected.

When the obstacle is fixed, the wave when it reaches the obstacle exerts a force on the point, by the law of action and reaction the point exerts on the wave a force of equal magnitude but in the opposite direction, this reaction force which makes the reflected wave is inverted.

When the obstacle is mobile, this is without friction, when the wave arrives it exerts a force on the mobile point, it moves in the direction of the wave, reaching the maximum amplitude of the incident wave, when it is reflected the point begins to go down along with the wave, therefore there is no inversion of it.

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A 45 g bug is hovering in the air. A gust of wind

MariettaO [177]

The work-done by the wind as the bug undergoes the displacement is 80 J.

The given parameters;

Mass of the bug, m = 45 g
Force exerted, F = (4.0 î – 6.0j) x 10⁻² N
Displacement of the bug, r = (8.0î - 8.0j) m

The work-done by the wind as the bug undergoes the displacement is obtained by finding the dot product of the force and the displacement;

Work done = F. r

Work done = (4.0 î – 6.0j) x 10⁻² . (8.0î - 8.0j)

Work done = (32i²) + (48j²)

Work done = 32(1) + 48(1)

Work done = 80 J.

Thus, the work-done by the wind as the bug undergoes the displacement is 80 J.

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3 years ago

Is there a difference between radial velocity and angular velocity or are they the same thing?

Novosadov [1.4K]

Angular velocity is the rate of change of angle of a body, i.e. omega = v / r = (2*pi*r)/ r*t = (2*pi)/ T. where T is the time period of whatever is rotating and r is the radius of the circle. So if a circular disc is spinning at 1 m/s then the angular velocity of it is 2*pi radians/ second.

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3 years ago

what is the magnitude of g at a height above earth surface where free fall acceleration equal 6.5m/s2

ZanzabumX [31]

The magnitude of gravity is expressed in terms of its acceleration. So the magnitude of ' g ' at that altitude is exactly 6.5 m/s^2.

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3 years ago

1. Earth releases about 44-46 Tw of heat, in fact heat can be converted into

Aleksandr [31]

Answer:

even if it all could be used, it wouldn't be enough

Explanation:

The land area of the US is about 5.45% of the world's area, so the amount of released heat over the area of the US is on the order of 2.4 Tw. Current technology for converting geothermal energy to electricity is about 12% efficient, so the available energy might amount to 0.29 Tw if it could all be captured.

Energy consumption in the US in 2019 was on the order of 0.46 Tw. This suggests that even if <em>all</em> of the thermal energy radiated by the Earth from the US could be turned to useful forms of energy, it would meet only about 60% of the US need for energy.

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4 years ago

A ski lift has a one-way length of 1 km and a vertical rise of 200 m. The chairs are spaced 20 m apart, and each chair can seat

rusak2 [61]

Power is needed for (1) acceleration and (2) lifting the loaded chairs. These two parts can be calculated separately and then added together.

(1) Power for acceleration:

The final speed of the lift is

V=(10 km/h)(1 h×1000 m60 sec×1 km)=2.887 m/s.

Then the power needed is

Pa=12m(V2−V20)/Δt=12(50×250 kg)(2.778 m/s)2=9.6 kW.

(2) Power for lift

Assume that the acceleration is constant (i.e. power supply is constant), its value will be

a=ΔVΔt=2.778 m/s5 s=0.556 m/s2.

Then the vertical lift during acceleration will be

(12at2)×(2001000)=1.36 m.

Hence, the power needed to increase the potential energy of the lift is

Pg=mgΔhΔt=(50×250 kg) (9.89 m/s2)(1.36 m)/(5 s)=3.41 kW.

Then the total Power required is

Ptotal=Pa+Pg=9.6+34.1=43.7 kW.

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2 years ago