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3 years ago

PLEASE ANSWER QUICK!! 3. Fill in the chart below to identify the properties of shape and volume for each type of matter.

Physics

1 answer:

Lady_Fox [76]3 years ago

6 0

Answer:

Shape / Volume

Solid Definite (holds shape) / Definite (fixed volume)

Liquid No definite shape (takes the shape of the container) / Definite (fixed volume)

Gas No definite shape (takes the shape of the container) / No definite volume (takes the volume of the container, but will expand indefinitely if not contained)

Explanation:

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A 150 g air-track glider is attached to a spring. The glider is pushed in 8.80 cm and released. A student with a stopwatch finds

Alla [95]

Answer:

2.06 N/m

Explanation:

The system makes 10.0 complete oscillations in 17.0 s. So, the frequency of the system is

$f=\frac{10.0}{17.0 s}=0.59 Hz$

The angular frequency of the system is given by

$\omega = 2\pi f=2\pi (0.59 Hz)=3.71 rad/s$

In a simple harmonic motion, the angular frequency is related to the mass and the spring constant by

$\omega=\sqrt{\frac{k}{m}}$

where

k is the spring constant

m is the mass

Here we know

$\omega=3.71 rad/s\\m = 150 g = 0.150 kg$

So we can solve the formula to find k:

$k=\omega^2 m = (3.71 rad/s)^2 (0.150 kg)=2.06 N/m$

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4 years ago

Which change in an abiotic factor causes coral bleaching? a. increased salinity b. decreased salinity c. decreased turbidity d.

Sedbober [7]

The answer is "d. increased temperature".

At the point when corals are stressed by changes in conditions, for example, temperature, light, or supplements, they remove the symbiotic algae living in their tissues, making them turn totally white. Hotter water temperatures can result in coral bleaching. At the point when water is too warm, corals will oust the algae living in their tissues, making the coral turn totally white. This is known as coral bleaching.

When a coral blanches, it isn't dead. Corals can endure a bleaching occasion, yet they are under more pressure and are liable to mortality.

7 0

3 years ago

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B. La velocidad de los electrones en los conductores metálicos es muy pequeña, del orden de algunos mm por segundo. ¿Cómo podría

Iteru [2.4K]

Answer:

electromagnetic wave. this energy is what lights the bulb.

Explanation:

When you close an electrical circuit, the electrons have a small drag speed, but the fluctuation of the electric field that is created originates by Lenz's law a magnetic field and the appearance of this magnetic field creates a fluctuating elective field, these two fields together forms a wave called an electromagnetic wave.

This electromagnetic wave has a speed given by the relation

v = √1 /ε μ

in a vacuum this speed is equal to the speed of light, which is worth 3 10⁸ m/s this very high value so the energy transported by this wave can travel the distance of 10 m in less than 10⁻⁷ s, This energy is what lights the bulb.

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4 years ago

A 81 kg man is riding on a 40 kg cart traveling at a speed of 2.3 m/s. He jumps off with zero horizontal speed relative to the g

Alexus [3.1K]

Answer:

$\Delta v= 4.66\frac{m}{s}$

Explanation:

In this case we have to use the Principle of conservation of Momentum:

This principle says that in a system the total momentum is constant if no external forces act in the system. The formula is:

$m_1v_1+m_2v_2=m_1u_1+m_2u_2$

Where:

$m_1:$ Mass of the first object.

$m_2:$ Mass of the second object.

$v_1:$ Initial velocity of the first object.

$v_2:$ Initial velocity of the second object.

$u_1:$ Final velocity of the first object.

$u_2:$ Final velocity of the second object.

In this problem we have:

$m_1=81kg\\m_2=40kg\\v_1_2=2.3\frac{m}{s}$

$u_1=0\frac{m}{s}$

Observation: $v_1_2:$ Is because the system has the same initial velocity.

First we have to find $u_2$ ,

$m_1v_1+m_2v_2=m_1u_1+m_2u_2$

We can rewrite it as:

$(m_1+m_2)v_1_2=m_1u_1+m_2u_2$

Replacing with the data:

$(m_1+m_2)v_1_2=m_1u_1+m_2u_2\\\\(81kg+40kg)2.3\frac{m}{s}=81kg(0\frac{m}{s})+40kg(u_2)\\\\(121kg)2.3\frac{m}{s}=40kg(u_2)\\\\\frac{(121kg)2.3\frac{m}{s}}{40kg}=u_2\\\\\frac{278.3}{40}\frac{m}{s}=u_2\\\\6.96\frac{m}{s}=u_2$

We found the final velocity of the cart, but the problem asks for the resulting change in the cart speed, this means:

$\Delta v=u_2-v_2\\\Delta v=6.96\frac{m}{s}-2.3\frac{m}{s}\\\Delta v= 4.66\frac{m}{s}$

Then, the resulting change in the cart speed is:

$\Delta v= 4.66\frac{m}{s}$

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3 years ago

Which of two factors influence the weight of an object due to gravitational pull?

Tresset [83]

The masses of the object and the planet it's on, and the distance between their centers.

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3 years ago

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