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WARRIOR [948]
3 years ago
7

You lift a 10-N physics book up in the air a distance of 1.0 m, at a constant velocity

Physics
1 answer:
Anarel [89]3 years ago
5 0

The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).

The force exerted on the book by gravity has magnitude

<em>F</em> = <em>mg</em> = (10 N) (9.80 m/s^2) = 9.8 N ≈ 10 N

You raise the book 1.0 m in the opposite direction, so the work done is

<em>W</em> = (10 N) (-1.0 m) = -10 J

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Two angles are supplementary. The first angle measures 40°. What is the measurement of the second angle?
e-lub [12.9K]

Supplementary angles add up to 180°. 
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None of those choices describes a plane. 
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The Fitness Log is:
Molodets [167]

Answer:

D.  A record of all the physical activity you complete in one week.

Explanation:

A "Fitness Log" allows you to keep track of your workout or exercise. Therefore, it is <em><u>a record of the different workout you've managed to complete within a time frame</u></em>. It gives you several information such as the<em> type of workout you've completed, its duration and the time of the day it was performed</em>. This makes a person motivated to exercise because he can see his progress. He may also include <em>his mood before and after workout</em> in order to become more mindful in exercising and many other things.

8 0
3 years ago
An object moving on a horizontal, frictionless surface makes a glancing collision with another object initially at rest on the s
Eddi Din [679]

Answer:

The correct answer is option 'a' 'The momentum is always conserved while as the kinetic energy may be conserved'

Explanation:

The conservation of momentum is a basic principle in nature which is always valid in an collision between 'n' number of objects if there are no external forces on the system. It is valid for both the cases weather the collision is head on or glancing or weather the object is elastic or inelastic.

The energy is only conserved in a collision that occurs on a friction less surface and the objects are purely elastic. Since in the given question it is mentioned that only the surface is friction less and no information is provided regarding the nature of the objects weather they are elastic or not hence we cannot conclusively come to any conclusion regarding the conservation of kinetic energy as the objects may be inelastic.

3 0
4 years ago
If a bullet loses 1/nth of its velocity while passing through a plank,then no of planks required to stop the bullet is?
Novay_Z [31]
Based on the answer provided, it seems the writer wanted you to assume that the energy loss per plank is constant. This is not the same as the bullet losing <span><span>1/nth</span><span>1/nth</span></span><span> of its velocity per plank (however, the fact that the question does not mention this assumption arguably makes the question ambiguous).

</span><span>With this assumption, the energy loss becomes
</span><span>
ΔE = <span>1/2 </span>m<span>v2 </span>− <span>1/2 </span>m <span><span>(<span>v−<span>v/n</span></span>) </span><span>2
</span></span></span>
and the number of planks <span>NN</span><span> becomes
</span>
N = <span><span><span>1/2</span>m<span>v2 /</span></span><span>ΔE </span></span>= <span><span>n2/ </span><span>2n−1
</span></span>
Otherwise, if you assume that the bullet loses <span><span>1/<span>nth</span></span><span>1/<span>nth</span></span></span><span> of its velocity per plank, then the answer is </span><span><span>N=∞</span></span><span><span>

</span>
</span>
8 0
3 years ago
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