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WARRIOR [948]
3 years ago
7

You lift a 10-N physics book up in the air a distance of 1.0 m, at a constant velocity

Physics
1 answer:
Anarel [89]3 years ago
5 0

The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).

The force exerted on the book by gravity has magnitude

<em>F</em> = <em>mg</em> = (10 N) (9.80 m/s^2) = 9.8 N ≈ 10 N

You raise the book 1.0 m in the opposite direction, so the work done is

<em>W</em> = (10 N) (-1.0 m) = -10 J

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The momentum of a 0.1 kg object traveling at 2000 m/s is 20,000 kg·m/s. True or False
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That's false.  

The definition of momentum is (mass) x (speed), so they must be multiplied.

"20,000 kg-m/s" has the correct units resulting from multiplication, but the number could only be the result of division.

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vovikov84 [41]

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What happens to parallel light rays that strike a concave lens?
torisob [31]

Answer:

They diverge on refraction

Explanation:

When parallel light rays strike a concave lens, they will diverge that is they spread out .

Concave lens is also known as diverging lens, which means that when parallel rays of light strike on it, the lens spreads out the light rays ( that is it diverges the rays of light) that are refracted through it.

At the middle  of concave lens is thinner.  

When light is passes through the lens they diverge it or spread out.

The concave lens causes light rays to bend away or diverge from its axis since the concave lens is a diverging lens.  

5 0
2 years ago
A snail moves 18 millimeters every 24 seconds what is the snails rate of speed
Nataly_w [17]

The speed of the snail is given by:

v=\frac{S}{t}

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The snail in the problem moves by S=18 mm in t=24 s, therefore its speed is

v=\frac{S}{t}=\frac{18 mm}{24 s}=0.75 mm/s


3 0
3 years ago
A ball of mass m is dropped from rest from a height h and collides elastically with the floor, rebounding to its original height
Jet001 [13]

Answer:

Explanation:

Given

mass m collides elastically with floor and jump to its original height I .e.velocity of rebound is same as the initial velocity

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so we need time to calculate the average force. So, option e is correct

3 0
2 years ago
Read 2 more answers
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