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Alexus [3.1K]
2 years ago
12

The drag force due to air resistance on a soccer ball traveling through the air at 20 m/s is 2.3 N. What is the drag force on th

at same soccer ball when it is moving through the air at 35.4 m/s
Physics
1 answer:
Aneli [31]2 years ago
3 0

The drag force on that same soccer ball when it is moving through the air at 35.4 m/s is 7.2 Newton.

Given the data in the question;

  • Initial speed; v_1 = 20m/s
  • Initial drag force; F_1 = 2.3N
  • Final speed; v_2 = 35.4m/s

Final drag force; F_2 =\ ?

From Newton's laws, Drag force is directly proportional to velocity squared:

F\ \alpha \ v^2 \\\\F = Kv^2

Where k is the constant of proportionality.

Hence;

\frac{F_1}{F_2} = \frac{V_1^2}{V_2^2}

We make "F_2" the subject of the formula

F_2 = \frac{F_1 * v_2^2}{v_1^2}

We substitute our values into the equation;

F_2 = \frac{2.3N * (35.4m/s)^2}{(20m/s)^2}\\\\F_2 = \frac{2.3N * 1253.16}{400} \\\\F_2 = \frac{2882.268N}{400}\\\\F_2 = 7.2N

Therefore, the drag force on that same soccer ball when it is moving through the air at 35.4 m/s is 7.2 Newton.

Learn more: brainly.com/question/2867185

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The melting point of potassium thiocyanate determined by a student in the laboratory turned out to be 174.5 oC. The accepted val
yaroslaw [1]

Answer:

0.75%

Explanation:

Measured value of melting point of potassium thiocyanate = 174.5 °C

Actual value of melting point of potassium thiocyanate = 173.2 °C

<em>Error in the reading = |Experimental value - Theoretical value|</em>

<em>= |174.5 - 173.2|</em>

<em>= |1.3|</em>

<em>Percentage error = (Error / Theoretical value) × 100</em>

<em>= (1.3 / 173.2)×100</em>

<em>= 0.75 %</em>

∴ Percentage error in the reading is 0.75%

4 0
2 years ago
What is the total momentum of a 30 kg object traveling left at 3 m/s and a 50 kg object traveling at 2 m/s to the right?
madam [21]

Answer:

there are 25 kg objective travelling at 2m/s to the right.

4 0
2 years ago
You have 4.9 g of an unknown substance. To identify the substance, you decide to measure its specific heat and find that it requ
kifflom [539]

The unknown substance can be lithium, which has a specific heat capacity of approximately 3.5 J/gK.

Explanation:

When heat energy is supplied to a certain substance, the temperature of the substance increases according to the equation:

Q=mC_s \Delta T

where

Q is the amount of energy supplied

m is the mass of the sample

C_s is the specific heat capacity of the substance

\Delta T is the change in temperature

In this problem, we have

m = 4.9 g is the mass

Q = 668.85 J is the specific heat capacity

\Delta T = 39 K is the change in temperature

Solving for C_s, we find the specific heat capacity of the substance:

C_s = \frac{Q}{m\Delta T}=\frac{668.85}{(4.9)(39)}=3.5 J/gK

Looking at tables of specific heat capacity, we can see that the unknown substance can be lithium, which has a specific heat capacity of approximately 3.5 J/gK.

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

3 0
2 years ago
What two bodily functions are increased by a warm up
drek231 [11]

1) Blood flow: increases during warming improving muscle and joint elasticity. This decreases the possibility of having an injury.


2) Body temperature: This causes the cellular metabolism to increase. It also causes vasodilatation that allows a greater supply of oxygen and nutrients.

6 0
3 years ago
The four tires of an automobile are inflated to a gauge pressure of 2.2 105 Pa. Each tire has an area of 0.023 m2 in contact wit
Stels [109]

Answer:

Force, F = 20240 N

Explanation:

It is given that,

Pressure exerted by the four tires of an automobile, P=2.2\times 10^5\ Pa

Area of each tire, A=0.023\ m^2

Area of 4 tires,  A=0.092\ m^2

We know that the pressure exerted by an object is equal to the force per unit area. Its formula is given by :

P=\dfrac{F}{A}

F=P\times A

F=2.2\times 10^5\times 0.092

F = 20240 N

So, the weight of the automobile is 20240 N. Hence, this is the required solution.

7 0
3 years ago
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