<em>hEy</em><em>!</em><em>!</em><em>!</em>
<em><u>Chlorine</u></em><em><u>(</u></em><em><u>CL</u></em><em><u>)</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>symbol</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>entity</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>has</u></em><em><u> </u></em><em><u>1</u></em><em><u>7</u></em><em><u> </u></em><em><u>protons</u></em><em><u>,</u></em><em><u>2</u></em><em><u>0</u></em><em><u> </u></em><em><u>neutrons</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>1</u></em><em><u>8</u></em><em><u> </u></em><em><u>electrons</u></em><em><u>.</u></em>
<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>helpful</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>you</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
11482 ppt of Li
Explanation:
The lithium is extracted by precipitation with B(C₆H₄)₄. That means moles of Lithium = Moles B(C₆H₄)₄. Now, 1 mole of B(C₆H₄)₄ produce the liberation of 4 moles of EDTA. The reaction of EDTA with Mg²⁺ is 1:1. Thus, mass of lithium ion is:
<em>Moles Mg²⁺:</em>
0.02964L * (0.05581mol / L) = 0.00165 moles Mg²⁺ = moles EDTA
<em>Moles B(C₆H₄)₄ = Moles Lithium:</em>
0.00165 moles EDTA * (1mol B(C₆H₄)₄ / 4mol EDTA) = 4.1355x10⁻⁴ mol B(C₆H₄)₄ = Moles Lithium
That means mass of lithium is (Molar mass Li=6.941g/mol):
4.1355x10⁻⁴ moles Lithium * (6.941g/mol) = 0.00287g. In μg:
0.00287g * (1000000μg / g) = 2870μg of Li
As ppt is μg of solute / Liter of solution, ppt of the solution is:
2870μg of Li / 0.250L =
<h3>11482 ppt of Li</h3>
Answer:
13-b
Explanation:
because 13-b is close to a and 12
2 K3PO4 + 3 BaCl2 = 6 KCl + Ba3(PO4)2
reaction type: double replacement
2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O
reaction type: double replacement
2 HCl + K2CO3 = 2 KCl + H2O + CO2
i think there are two reactions here, so double replacement and decomposition
2 AgNO3 + Na2CO3 = Ag2CO3 + 2 NaNO3
reaction type: double replacement
2 Al2O3 = 4 Al + 3 O2
reaction type: decomposition