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Yuliya22 [10]
3 years ago
8

The Chandrasekhar limit states that the final mass of a _____ star can be no greater than 1.4 solar masses.

Chemistry
2 answers:
Anton [14]3 years ago
8 0
The answer is a white dwarf star 
Marrrta [24]3 years ago
6 0
Stable white dwarf star
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A piece of wood near a fire is at 23°c. it gains 1,160 joules of heat from the fire and reaches a temperature of 42°c. the speci
Alex73 [517]

The mass of the piece of wood is 35.58 g.

Joule = M × T × C

Where, M = mass

T = change in temperature(42C-23C=19 C)

C = specific heat capacity = 1.716 joules/gram

Substituting the values in the equation,

1160 = M × 19 × 1.716

M = 1160/32.604 = 35.58 g

Therefore, the mass of the piece of wood = 35.58 g

<h3>What is meant by specific heat capacity?</h3>

A material's specific heat capacity, which is defined as its heat capacity divided by its mass, determines how much energy is required to increase a gram's temperature by one degree Celsius (or one Kelvin)

<h3>What is mass?</h3>

Mass is the quantity of matter in a physical body.

To learn more about specific heat capacity visit:

brainly.com/question/1747943

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7 0
1 year ago
What do parent and daughter cells have in<br> common? Check all that apply.
Vera_Pavlovna [14]

Answer:

Mitosis is common to all eukaryotes; during this process, a parent cell splits into two genetically identical daughter cells, each of which contains the same number of chromosomes as the parent cell.During meiosis, the cells needed for sexual reproduction divide to produce new cells called gametes.

5 0
3 years ago
Which of the following refers to a chemical property
LuckyWell [14K]
Reactivity<span> refers to a chemical property </span>
8 0
4 years ago
Calculate the equilibrium constant for the following reaction: Co2+ (aq) + Zn(s&gt; CO (s) + Zn2+ (aq)
Simora [160]

<u>Answer:</u> The K_{eq} of the reaction is 1.73\times 10^{16}

<u>Explanation:</u>

For the given half reactions:

Oxidation half reaction: Zn(s)\rightarrow Zn^{2+}+2e^-;E^o_{Zn^{2+}/Zn}=-0.76V

Reduction half reaction: Co^{2+}+2e^-\rightarrow Co(s);E^o_{Co^{2+}/Co}=-0.28V

Net reaction: Zn(s)+Co^{2+}\rightarrow Zn^{2+}+Co(s)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=-0.28-(-0.76)=0.48V

To calculate equilibrium constant, we use the relation between Gibbs free energy, which is:

\Delta G^o=-nfE^o_{cell}

and,

\Delta G^o=-RT\ln K_{eq}

Equating these two equations, we get:

nfE^o_{cell}=RT\ln K_{eq}

where,

n = number of electrons transferred = 2

F = Faraday's constant = 96500 C

E^o_{cell} = standard electrode potential of the cell = 0.48 V

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = 25^oC=[273+25]=298K

K_{eq} = equilibrium constant of the reaction = ?

Putting values in above equation, we get:

2\times 96500\times 0.48=8.314\times 298\times \ln K_{eq}\\\\K_{eq}=1.73\times 10^{16}

Hence, the K_{eq} of the reaction is 1.73\times 10^{16}

8 0
3 years ago
Which particle has the most energy?
Bess [88]

Answer:

water energy yes y *jjjjjjjjjj

6 0
4 years ago
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