Answer:
The concentration of the acid is about 0.114 M (option E)
Explanation:
Step 1: Data given
Volume of the monoprotic acid = 25.0 mL = 0.025 L
Molarity of the monoprotic acid = ?
Molarity of the NaOH solution = 0.115 M
Volume NaOH = 24.8 mL = 0.0248 L
Step 2: Calculate the concentration
a*Cb * Vb = b * Ca * Va
⇒ a = the coeficient of NaOH = 1
⇒ Cb = the molarity of the acid = TO BE DETERMINED
⇒ Vb = the volume of the acid = 0.025 L
⇒ b = the coefficient of the acid = monoprotic = 1
⇒ Ca = the moalrity of NaOH = 0.115 M
⇒ Va = the volume of NaOH = 0.0248 L
1 * Cb * 0.025 = 1 * 0.115 * 0.0248
0.025 Cb = 0.002852
Cb = 0.11408 M
The concentration of the acid is about 0.114 M
Explanation:
Below is an attachment containing the solution.
It is an alkene: CnH2n (n=number of the atoms of carbon)
in ethylene there are two carbons so:
C2H4 just like the picture
Answer:
I think the answer is the 3rd one
Answer:
67.93 kg.
Explanation:
See the attached pictures for detailed explanation.