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Talja [164]
3 years ago
14

The most common source of copper (Cu) is the mineral chalcopyrite (CuFeS2). How many kilograms of chalcopyrite must be mined to

obtain 210. g of pure Cu?
Chemistry
2 answers:
kicyunya [14]3 years ago
8 0
To find out the answer, we must know the mass percentage of Cu in the mineral chalcopyrite.

Mass percentage of Cu = molar mass of Cu/molar mass of chalcopyrite = 64/(64+56+32*2) = 34.8%.

So to obtain 210 g pure Cu, the amount of mineral need = mass of Cu/mass percentage of Cu = 210 g/34.8% = 603 g = 0.603 kg.
andriy [413]3 years ago
7 0
The molecular weight of chalcopyrite is equivalent to 183.53 grams which is made up of copper 63.56 g, iron 55.85 g and sulphur 64.12 g for a total of 183.53 g and so copper is 63.56/183.53=34.63%. So then, kg chalcopyrite x 0.3463=210 g or 0.21 kg pure Cu so kg chalco = 0.21/0.3463=0.606 kg chalcopyrite.
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uysha [10]

Answer:

d. 12.3 grams of Al2O3

Explanation:

The balanced chemical equation of this chemical reaction is as follows:

4Al + 3O2 --> 2Al2O3

Based on the balanced equation, 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

First, we need to convert the mass of aluminum to moles using the formula;

mole = mass/molar mass

Molar mass of Al = 27g/mol

mole = 6.50/27

= 0.241mol of Al.

Hence, if 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

Then, 0.241mol of Al will produce (0.241 × 2/4) = 0.241/2 = 0.121mol of Al2O3.

Convert this mole value to molar mass using mole = mass/molar mass

Molar mass of Al2O3 = 27(2) + 16(3)

= 54 + 48

= 102g/mol

mass = molar mass × mole

mass = 102 × 0.121

mass of Al2O3 = 12.34grams.

5 0
3 years ago
Please help due soon.
Vikentia [17]

Answer:

water - Yes because the do drink water

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Explanation:

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3 0
3 years ago
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when 6.25 grams of pure iron are allowed to react with oxygen , a black oxide forms. if the product weighs 8.15 g, what is the e
erik [133]
We are given with the mass of  pure iron that reacts with oxygen to form an oxide which has a given mass as well. the mass of oxygen reacted is 8.15-6.25 g or 1.9 grams. THen we convert the mass of the reactants to moles. Iron is equal to 0.1119 moles and oxygen is equal to 0.1188. We divide each number to the less amount. Hence iron is 1 and oxygen is approx 1. The empirical formula hence is FeO or ferrous oxide or Iron (II) oxide.
5 0
3 years ago
How do i calculate the concentration of a certain solution​
Nuetrik [128]

Answer:

Divide the mass of the solute by the total volume of the solution. Write out the equation C = m/V, where m is the mass of the solute and V is the total volume of the solution. Plug in the values you found for the mass and volume, and divide them to find the concentration of your solution.

3 0
3 years ago
Three different samples were weighed using a different type of balance for each sample. The three were found to have masses of 0
Lena [83]

Answer:

6.096799125kg

Explanation:

According to the question, three different samples weighed using different types of balance had masses: 0.6160959 kg, 3.225 mg, and 5480.7 g.

Based on observation, the mass units in the three measurements are different but must be uniform in order to find the total mass. Hence, we need to convert to the standard unit (S.I unit of mass), which is kilograms (kg)

Since 1kg equals 1,000,000mg

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= 0.000003225kg

Also, 1kg equals 1000g

Hence, 5480.7g will be 5480.7/1000

= 5.4087kg

Hence, the total mass of the three samples (now in the same unit) are:

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= 6.096799125kg

3 0
3 years ago
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