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Mekhanik [1.2K]
3 years ago
14

A study found that highway drivers in one state traveled at an average speed of 56.6 miles per hour​ (MPH). Assume the populatio

n standard deviation is 5.1 MPH. Complete parts a through d below.
a. What is the probability that a sample of 30 of the drivers will have a sample mean less than 56 ​MPH?
b. What is the probability that a sample of 45 of the drivers will have a sample mean less than 56 ​MPH?
c. What is the probability that a sample of 60 of the drivers will have a sample mean less than 56​ MPH?
d. Explain the difference in these probabilities. (Select one each)

i. As the sample size​ increases, the standard error of the mean
(Same, Increase, Decrease)
ii. As the sample size​ increases, the standard error of the mean
(Same, Move farther, Move closer) the population mean of 57.3 MPH.​
iii. Therefore, the probability of observing a sample mean less than 56 MPH
(Same, Increase, Decrease).
Mathematics
1 answer:
DaniilM [7]3 years ago
4 0

Answer:

a) 25.78% probability that a sample of 30 of the drivers will have a sample mean less than 56 ​MPH

b) 21.48% probability that a sample of 45 of the drivers will have a sample mean less than 56 ​MPH

c) 18.14% probability that a sample of 60 of the drivers will have a sample mean less than 56​ MPH

d)

i. As the sample size​ increases, the standard error of the mean

decreases

ii. As the sample size​ increases, the standard error of the mean

move farther the population mean of 57.3 MPH.​

iii. Therefore, the probability of observing a sample mean less than 56 MPH

decrease.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 56.6, \sigma = 5.1

a. What is the probability that a sample of 30 of the drivers will have a sample mean less than 56 ​MPH?

This means that s = \frac{5.1}{\sqrt{30}} = 0.93

This probability is the pvalue of Z when X = 56. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{56 - 56.6}{0.93}

Z = -0.65

Z = -0.65 has a pvalue of 0.2578.

25.78% probability that a sample of 30 of the drivers will have a sample mean less than 56 ​MPH

b. What is the probability that a sample of 45 of the drivers will have a sample mean less than 56 ​MPH?

s = \frac{5.1}{\sqrt{45}} = 0.76

Z = \frac{X - \mu}{s}

Z = \frac{56 - 56.6}{0.76}

Z = -0.79

Z = -0.79 has a pvalue of 0.2148.

21.48% probability that a sample of 45 of the drivers will have a sample mean less than 56 ​MPH

c. What is the probability that a sample of 60 of the drivers will have a sample mean less than 56​ MPH?

s = \frac{5.1}{\sqrt{60}} = 0.66

Z = \frac{X - \mu}{s}

Z = \frac{56 - 56.6}{0.66}

Z = -0.91

Z = -0.91 has a pvalue of 0.1814.

18.14% probability that a sample of 60 of the drivers will have a sample mean less than 56​ MPH

d. Explain the difference in these probabilities. (Select one each)

n increases, so s decreases(moving farther from the mean), which means that z decreases, leaving 56 mph to a lower percentile. So

i. As the sample size​ increases, the standard error of the mean

decreases

ii. As the sample size​ increases, the standard error of the mean

move farther the population mean of 57.3 MPH.​

iii. Therefore, the probability of observing a sample mean less than 56 MPH

decrease.

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