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3 years ago

Most earthquakes happen:

Physics

2 answers:

denpristay [2]3 years ago

6 0

they happen around the edge of the plates in the earth.

they are moving in different directions so occasionally they rub together causing a earthquake.

hope this helps

umka2103 [35]3 years ago

4 0

Along plate edges, at points where oceanic or continental plates meet ot at the edges of the plates

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Using the right-hand rule from your lessons, determine the directions of the electrical current and magnetic field of the electr

aliya0001 [1]

Answer:

Hello there use something that looks like this

Explanation:

This is an accurate representation of something you are working on!

As you can see the wire and the core are represented on the left and is showing how it can be represented on your right hand and how they are similar!

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4 years ago

A test rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward

Romashka-Z-Leto [24]

The rocket starts at rest, so its initial velocity is 0. If the burn phase lasts $t$ seconds, then during this interval the rocket's velocity is

$v=at\implies a=\dfrac{30\,\frac{\mathrm m}{\mathrm s}}t$

and its position is

$x=\dfrac12at^2\implies a=\dfrac{2(49\,\mathrm m)}{t^2}$

So we have

$\dfrac{30\,\frac{\mathrm m}{\mathrm s}}t=\dfrac{2(49\,\mathrm m)}{t^2}\implies t=3.3\,\mathrm s$

and the answer is C.

4 0

3 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Yuliya22 [10]

Answer: The mean of the samples is 32.325.

Proportion of the defective unit is = $\frac{2}{40}=\frac{1}{20}=0.05$

Explanation:

The point estimate of the mean of the sample:

First calculate the mean of the 40 samples:

$\frac{\text{Sum of all the samples}}{\text{Number of observations}}$

$\frac{1,293}{40}=32.325$

The mean of the samples is 32.325.

Defected pieces in the samples whose life span is less than the 26 days = 2

Proportion of the defective unit is = $\frac{2}{40}=\frac{1}{20}=0.05$

7 0

4 years ago

Read 2 more answers

In a weak acid solution, _____.

erastovalidia [21]

Answer:

Explanation:

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3 years ago

You push on the top edge of a 1.8 m tall solid circular cylinder of iron which is 4.00 cm in diameter. You push with a horizonta

Citrus2011 [14]

Answer:

$\triangle x=3.2*10^-^5 m$

Explanation:

From the question we are told that

Height of circular cylinder is $h= 1.8m$

Diameter of cylinder $D=4cm=>0.04m$

Horizontal Force $F=900N$

$Y = 10.0 *10^1^0 N/m^2 \\B = 9.0 * 10^1^0 N/m^2\\S = 4.0 * 10^1^0 N/m^2\\$

Generally the formula for shear modulus is mathematically represented by

$G=\frac{\tau}{\gamma}$

Where

$G=Shear modulus\\\tau= shear\ stress\\\gamma=shear strain$

$G=\frac{F/A}{\triangle x/L}$

$G=\frac{900/\pi r^2}{\triangle x/1.8}$

$4.0*10^1^0=\frac{900/\pi r^2}{\triangle x/1.8}$

$4.0*10^1^0=\frac{900}{\pi r^2} *\frac{1.8}{\triangle x}$

${\triangle x} =\frac{1620}{\pi r^2* 4.0*10^1^0}$

$\triangle x=3.2*10^-^5 m$

5 0

3 years ago