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svetoff [14.1K]
3 years ago
15

We are all familiar with the general principles of operation of an internal combustion engine: the combustion of fuel drives out

the piston. It is possible to imagine engines that use reactions other than combustions, and we need to assess the work they can do. A chemical reaction takes place in a container of cross-sectional area 100.0 cm^2; the container has a piston at one end. As a result of the reaction, the piston is pushed out through 10 cm against a constant external pressure of 100 kPa. Calculate the work done by the system in Joules.
Chemistry
1 answer:
Alexus [3.1K]3 years ago
7 0

Answer:

The work done by the system is 100 J

Explanation:

Given details

The cross sectional area of the of the container is A = 100.0 cm^2 = 0.01m²

The total distance pushed by the piston is d = 10 cm = 0.10m

The total external pressure by which piston pushed is P = 100 kPa

From above data, the following relation can be used to determine the change in volume of the container

∆V = A * d

∆V = 0.01 * 0.10 = 0.001 m³

By using the following relation, the work done by the system is calculated as;

Work done W = P * ∆V

W = 100 * 0.001 = 0.1 kJ = 100 J

The work done by the system is 100 J

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<h3><u>Answer;</u></h3>

3p34s23d7

<h3><u>Explanation</u>;</h3>
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3.) this graph shows the rates of reaction in a chemical reaction with and without the addition of an enzyme
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Answer:

a. Concave down

Linear increasing

b. Increases the reaction rate

c. The reaction approaches the saturation point of the enzyme

Explanation:

a. For the reaction with enzyme, the shape is concave down. The action of the enzyme on the preferred substrate is initially very rapid and decreases as the enzyme becomes saturated and the ratio of products to substrate increases to approach an equilibrium rate of reaction

For the reaction without enzyme, the shape is linear and increasing. Increase in the concentration of the substrate will increase the number of effective collisions that lead into product formation leading to an increased rate of the chemical reaction

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Answer:

5.158 × 10²³ atoms K

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
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Explanation:

<u>Step 1: Define</u>

33.49 g K

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Avogadro's Number

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