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Ahat [919]
3 years ago
15

Cone A has a height of 3 meters and a radius of 2 meters. Cone B has the same radius, but the height is 6 meters. Calculate the

Mathematics
1 answer:
tiny-mole [99]3 years ago
3 0
The volume of cone B is twice the volume of cone A.

Explanation:
For cone A,
Radius (r)= 2m
Height (h) = 3m
Volume of cone A (V1) = 1/3 Pi r^2 *h
=1/3 * 22/7 * 2^2 *3
=264/21
=88/7
=12.571,,

For cone B,
r= 2m
h= 6m
Volume of cone B (V2) = 1/3 Pi r^2*h
=1/3 * 22/7 * 2^2 * 6
=528/21
=176/7
=25.142,,

It is seen that,
V2= 2*V1
25.142 = 2*12.571
25.142 = 25.142, which is true.
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A probability experiment is conducted in which the sample space of the experiment is Sequals=StartSet 9 comma 10 comma 11 comma
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Answer:

From both approaches P(F or G)=0.667

Step-by-step explanation:

P(F or G)=?

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G={13,14,15,16}

Finding P(F or G) by counting outcomes in F or G

F or G={9, 10, 11, 12, 13}or {13,14,15,16}

F or G={9, 10, 11, 12,13,14,15,16}

number of outcomes in F or G=n(F or G)=8

S={9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}​

number of outcomes in S=n(S)=12

P(F or G)=n(F or G)/n(S)

P(F or G)=8/12

P(F or G)=0.667

Finding P(F or G) by addition rule

P(F or G)=P(F)+P(G)-P(F and G)

F={9, 10, 11, 12, 13}​

number of outcomes in F=n(F)=5

P(F)=n(F)/n(S)

P(F)=5/12

P(F)=0.417

G={13,14,15,16}

number of outcomes in G=n(G)=4

P(G)=n(G)/n(S)

P(G)=4/12

P(G)=0.333

F and G={9, 10, 11, 12, 13}and {13,14,15,16}

F and G={13}

number of outcomes in F and G=n(F and G)=1

P(F and G)=n(F and G)/n(S)

P(F and G)=1/12

P(F and G)=0.083

P(F or G)=P(F)+P(G)-P(F and G)

P(F or G)=0.417+0.333-0.083

P(F or G)=0.667

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find the area of the metal sheet below that is required to make this square-shaped traffic sign. one side is labeled 8x-1.
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