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3 years ago

14

When you have 25 numbers, and Jake picks 3 random numbers and puts them back, what is the chance Bob has of picking those 3 numb

ers when he picks 6 random numbers (without putting them back)?
Please explain.

1 answer:

tensa zangetsu [6.8K]3 years ago

7 0

Answer:

4 out of 25 percent chance

Step-by-step explanation:

if you divide the number and range them out. That's all i can tell you for now. Kinda busy. sorry

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Oliga [24]

Step-by-step explanation:

1a. Just add both of them.

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1b. We just subtract both of the functions.

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$4x - 8$

1c.

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1d.

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2 years ago

Warren has a container which holds 22 books of the same shape and size. The exact breakdown of his books is shown below:

ohaa [14]

Given:

Total number of book = 22

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To find:

The probability that Warren takes out a green book in both draws (with replacement).

Solution:

We know that,

$\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}$

$P(\text{White})=\dfrac{6}{22}$

$P(\text{Purple})=\dfrac{9}{22}$

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After replacement, the probability of event remains the same and the independent.

The probability that Warren takes out a green book in both draws is:

$P=P(\text{green})\times P(\text{green})$

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$P=\dfrac{49}{484}$

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3 years ago

Victoria has $200 of her birthday gift money saved at home, and the amount is modeled by the function h(x) = 200. She reads abou

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Solution :

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No because she runs up yes but she also ran down witch means she went exactly 0

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natta225 [31]

The Answer is C. 2 it's not that difficult of an equation.

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