As the frequency is how many waves pass a fixed point in certain amount of times. This means that the waves get closer together and, therefore, the wavelength decreases. It also means that the wave has more energy.
Answer: D) Energy increases, wavelength decreases
This element is beryllium.
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Oil molecules like to stick to other oil molecules more than they like to stick to water molecules. This is because mineral oil has nonpolar molecules and water has polar ones.
Atoms show us the basic proverb about the strength and the bond when they are Unity and Diversified.
<u>Explanation:</u>
- Every basic matter in the earth is composed of atoms. It is the smallest unit of the matter which is taken to observe the properties of the whole element.
- The atom consists of different energy levels and consist of protons electrons and neutrons.
- The atoms when are compactly arranged it result in the great strength required to bring the deformation in shape which shows that unity is always great.
- But in the liquid and gas, the atoms are arranged in a randomly dispersed pattern which shows that they can be separated and involved in any process easier to get the heterogeneous product easily which is an example for Diversity.
The
equation for the photosynthesis reaction in which carbon dioxide and water
react to form glucose is .
The hear reaction is the difference between the bond dissociation energies in
the products and the bond dissociation energies of the reactants
The
reactant molecules have 12 C = O, 12 H - O bonds while the product molecules
have 5 C - C, 7 C – O, 5 H – O, and 6 O = O bonds. The average bond
dissociation energies for the bonds involved in the reaction are 191 for C = O,
112 for H – O, 83 C –C, 99 C – H, 86 C – O, 119 O = O.
Substitute
the average bond dissociation energies in the equation for and
calculate as follows
=
[12 (C=O) + 12 (H-O)] – [5(C-C) + 7(C-H) + 7 (C-O) + 5(H-O) + 6(O=O)]
=
[12x191 kcal/mol + 12x112 kcal//mol] – [5x83 kcal/mol + 7x99 kcal/mol + 7x86
kcal/mol + 5x112 kcal/mol + 6x119 kcal/mol]
=
3636 kcal/mol – 2984 kcal/mol = 652 kcal/mol x 4.184 Kj/1kcal = 2.73x10^3 kJ/mol
So,
enthalpy change for the reaction is 652 kcal/mol or 2.73x10^3 kJ/mol
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