Answer:
The net change in the internal energy of the gas in the piston is -343J
Explanation:
Because heat and workdone are the only means of energy transfer between the system and the surrounding, change in internal energy is given by;
∆E = q + w
q = heat transfer
w = workdone
Because heat is lost by the system, the heat transfer is negative
q = -413J
Because work is done on the system, workdone is positive
w = +70J
∆E = -413J + 70J
∆E = -343J
Answer:
(a) 4.38 s.
(b) 1.817 s
Explanation:
(a)
Using
θ = ω₀t +1/2αt² ................ Equation 1
Where θ = number of revolution, t = time, α = angular acceleration, ω₀ = angular velocity.
Given: θ = 1.59 rev = 1.59×2π = 9.992 rad, ω₀ = 0 rad/s, α = 1.04 rad/s².
Substitute into equation 1
9.992 = 0(t) + 1/2(1.04)(t²)
t² = (2×9.992)/1.04
t² = 19.984/1.04
t = √(19.215)
t =4.38 s.
(b)
also using
θ = ω₀t +1/2αt²............... Equation 1
Given: θ =3.18 rev = 3.18×2π = 19.97 rad, ω₀ = 0 rad/s, α = 1.04 rad/s².
Substitute into equation 1
19.97 = 0(t) + 1/2(1.04)(t²)
t² = 19.97×2/1.04
t = √(38.40)
t = 6.197 s
The time require = 6.197-4.38 = 1.817 s
If a conductor wire is heated, its resistance decreases and conductivity increases.
In Exercises 58 - 73, use the graph of y = f(x) given below to answer the question. x y. -4 -3 -2 -1. 1. 2. 3. 4.
Answer:
i think it would be B. Aluminum, Al and D. Boron, B
Explanation:
since they're both in group 13 and they forms a 3+ ion
