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Elenna [48]
3 years ago
14

A ball is tossed into the air from height of 8 feet with an initial velocity of 8 feet per second. find the time r(in seconds) i

t takes for the object to reach the ground by solving the equation -16t + 8t + 8 = 0 you trimmed a large strip of wallpaper from a scrap to fit into the corner of a wall you are wallpapering. you trimmed 15 inches from the length
Physics
1 answer:
-Dominant- [34]3 years ago
3 0
For this case we have the following equation:
 -16t + 8t + 8 = 0
 The first thing we must do is rewrite the equation correctly.
 We have then:
 -16t ^ 2 + 8t + 8 = 0
 Solving the polynomial we have:
 t1 = -1/2
 t2 = 1
 We discard the negative root because we want to find the time.
 Answer:
 it takes for the object to reach the ground about:
 t = 1 second
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An adiabatic nozzle has an inlet area of 1 m^2 and an outlet area of 0.25 m^2. Water enters the nozzle at a rate of 5 m^3/s and
svlad2 [7]

Answer:

v=20m/S

p=-37.5kPa

Explanation:

Hello! This exercise should be resolved in the next two steps

1. Using the continuity equation that indicates that the flow entering the nozzle must be the same as the output, remember that the flow equation consists in multiplying the area by the speed

Q=VA

for he exitt

Q=flow=5m^3/s

A=area=0.25m^2

V=Speed

solving for V

V=\frac{Q}{A} \\V=\frac{5}{0.25} =20m/s

velocity at the exit=20m/s

for entry

V=\frac{5}{1} =5m/s

2.

To find the pressure we use the Bernoulli equation that states that the flow energy is conserved.

\frac{P1}{\alpha } +\frac{v1^2}{2g} =\frac{P2} {\alpha } +\frac{v2^2}{2g}

where

P=presure

α=9.810KN/m^3 specific weight for water

V=speed

g=gravity

solving for P1

(\frac{p1}{\alpha } +\frac{V1^2-V2^2}{2g})\alpha  =p2\\(\frac{150}{9.81 } +\frac{5^2-20^2}{2(9.81)})9.81  =p2\\P2=-37.5kPa

the pressure at exit is -37.5kPa

7 0
4 years ago
You decide to ride your bike for 30 minutes, raising your heart rate to the middle of your target heart rate zone. What type of
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Lilly covered the same distance in less time, and both girls
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Answer:

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