A ball is tossed into the air from height of 8 feet with an initial velocity of 8 feet per second. find the time r(in seconds) i
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Answer:
v = 2,425 m / s
Explanation:
A simple pendulum has anergy stored at the highest point of the path and this energy is conserved throughout the movement.
highest point
Em₀ = U = m g y
lowest point
= K = ½ m v²
Em₀ = Em_{f}
mg y = ½ m v²
v = √ 2gy
let's calculate
v = √ (2 9.8 0.3)
v = 2,425 m / s
Solution :
Given :
Rectangular wingspan
Length,L = 17.5 m
Chord, c = 3 m
Free stream velocity of flow, = 200 m/s
Given that the flow is laminar.
So boundary layer thickness,
= 0.0024 m
The dynamic pressure,
The skin friction drag co-efficient is given by
= 0.00021
= 270 N
Therefore the net drag = 270 x 2
= 540 N