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2 years ago

9

a truck starts to move from rest if it given the acceleration of 3 metre per second square in 5 second calculate the final veloc

ity and distance covered by truck in full process

1 answer:

frosja888 [35]2 years ago

7 0

Hope this helps. Plzz let me know if you have any further doubts :)

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Suppose a rock is dropped off a cliff with an initial speed of 0m/s. What is the rocks speed after 5 secounds, in m/s, if it enc

Tasya [4]

Answer:

The rock's speed after 5 seconds is 98 m/s.

Explanation:

A rock is dropped off a cliff.

It had an initial velocity of 0 m/s. And now it is moving downwards under the influence of gravitational force with the gravitational acceleration of 9.8 m/s².

Speed after 5 seconds = V

We know that acceleration = average speed/time

In our case,

g = ((0+V)/2)/5

9.8*5 = V/2

=> V = 2*9.8*5

V = 98 m/s

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3 years ago

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Eric has a mass of 70 . He is standing on a scale in an elevator that is accelerating downward at 1.7 . What is the approximate

pychu [463]

Answer:

B)

Explanation:

The value the scale shows is the reaction force to the normal force (they are equal by Newton's 3rd Law) that the scale exerts on Eric.

The forces on Eric are his weight (downward) and this normal force (upward), so we can write the net force over him as (also using Newton's 2nd Law):

$F=W-N=ma$

which means

$N=W-ma=mg-ma=m(g-a)$

and for our values this is:

$N=mg-ma=(70kg)(9.8m/s^2-1.7m/s^2)=567N$

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3 years ago

A 10 kg brick and a 1 kg book are dropped in a vacuum. The force of gravity on the 10 kg brick is what?

Nadya [2.5K]

<span>10 times as much. Since F=m*a, and a is constant, the only thing that affects force is the mass.

In response to the below answer, the acceleration due to gravity does not change. The force due to gravity definitely DOES change depending on the mass of the object. Since the force is what the problem asks for, the answer is 10</span>

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3 years ago

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Why are common measurement systems important

kenny6666 [7]

So that international people don't mistake units for others. ex 1 inch could be mistaken for 1 cm in non American countries

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3 years ago

A stoppered test tube traps 25.0 cm3 of air at a pressure of 1.00 atm and temperature of 18OC. The cylindrically shaped stopper

storchak [24]

Explanation:

The pressure of an object is calculated as follows: $P = \frac{F}{A}$

The area of test tube stopper is A= π $r^{2}$

Since radius is half the diameter we have the following:

R = $\frac{1.20 cm}{2}$ = 0.60 cm

Thus the area of the test tube becomes:

A = π $( 0.60 Cm)^{2}$

= π $(0.006 m) ^{2}$

= 1.14 * $10^{-4} m^{2}$

Now the force from the outside of the tube.

$F_{out} = P_{out} A$

= $( 1.013 * 10^{5} Pa ) ( 1.14 * 10^{-4} m^{2} )$

= 11.55N

The net upward force on the stopper is equal to the difference of force exerted by pressure from inside of the tube and that from the outside.

$F_{Net} = F_{In} - F_{Out}$

$F_{In} = F_{Net} + F_{Out}$

$F_{In} = 11.5N + 11.55N$

= 23.1 N

8 0

3 years ago