At Jones College, there are a total of 100 students.

Convert 2000 g/l to the unit g/ml

balu736 [363]

$\frac{2 \000 g}{l} = \ ? \ \frac{g}{ml} \\ \\ 1 \ l = 1 \ 000 \ ml \\ \\\frac{2\ 000 \ g}{l} =\frac{2 \000 \ g}{1 \000\ ml} = 2.0 \ \ \frac{g}{ml}$

6 0

2 years ago

Read 2 more answers

Find X and QT. The shape is a Rhombus

kompoz [17]

Answer:

See below ~

Step-by-step explanation:

Sides of a rhombus are equal.

⇒ QT = TS

⇒ x² - 4x - 10 = 6x + 14

⇒ x² - 10x - 24 = 0

⇒ x² + 2x - 12x - 24 = 0

⇒ x (x + 2) - 12 (x + 2) = 0

⇒ (x + 2)(x - 12) = 0

⇒ x = -2 or x = 12

Substitute both values and see which gives a positive value for QT :

When x = -2 :

QT = (-2)² - 4(-2) - 10
QT = 4 + 8 - 10
QT = 2

When x = 12 :

QT = (12)² - 4(12) - 10
QT = 144 - 48 - 10
QT = 86

The 2 possible answers are :

x = -2, QT = 2
x = 12, QT = 86

8 0

1 year ago

Two people start from the same point. One walks east at 4 mi/h and the other walks northeast at 8 mi/h. How fast is the distance

kvasek [131]

Answer:

5.89 mi/h

Step-by-step explanation:

This problem can be solved by using different methods. I will use vectors since it's the simplest way in which we can solve it. This can be solved by using related rates of change though.

First, we start by drawing a diagram with the velocity vectors.

A= velocity of the first person

B= velocity of the second person

C= velocity in which they are moving away from each other.

Since there is no acceleration in the problem, we can suppose we are talking about constant speeds, so the velocity at which they are moving away from each other will always remain constant. (It doesn't matter what time it is, the velocity will always be the same)

Having said this we can solve this problem by using the components, by using law of cosines or graphically. I will use law of cosines. The idea is to find the length of side c.

Law of cosines:

$C^{2}=A^{2}+B^{2}-2ABcos \gamma$

so we can solve the formula for C so we get:

$C=\sqrt{A^{2}+B^{2}-2ABcos \gamma}$

and now we can substitute the values we know:

$C=\sqrt{(4)^{2}+(8)^{2}-2(4)(8)cos 45^{o}}$

$C=\sqrt{16+64-32\sqrt{2}}$

$C=\sqrt{80-32\sqrt{2}} mph$

if we want an exact answer, then that will be the exact answer, which approximates to:

C=5.89 mph

4 0

3 years ago

Which score indicates the highest relative position? I. A score of 2.6 on a test with X = 5.0 and s = 1.6 II. A score of 650 on

Zanzabum

Answer:

A score of 2.6 on a test with $\bar X$ = 5.0 and s = 1.6 and A score of 48 on a test with $\bar X$ = 57 and s = 6 indicate the highest relative position.

Step-by-step explanation:

We are given the following:

I. A score of 2.6 on a test with $\bar X$ = 5.0 and s = 1.6

II. A score of 650 on a test with $\bar X$ = 800 and s = 200

III. A score of 48 on a test with $\bar X$ = 57 and s = 6

And we have to find that which score indicates the highest relative position.

For finding in which score indicates the highest relative position, we will find the z score for each of the score on a test because the higher the z score, it indicates the highest relative position.

The z-score probability distribution is given by;

Z = $\frac{X-\bar X}{s}$ ~ N(0,1)

where, $\bar X$ = mean score

s = standard deviation

X = each score on a test

The z-score of First condition is calculated as;

Since we are given that a score of 2.6 on a test with $\bar X$ = 5.0 and s = 1.6,

So, z-score = $\frac{2.6-5}{1.6}$ = -1.5 {where $\bar X = 5.0$ and s = 1.6 }

The z-score of Second condition is calculated as;

Since we are given that a score of 650 on a test with $\bar X$ = 800 and s = 200,

So, z-score = $\frac{650-800}{200}$ = -0.75 {where $\bar X = 800$ and s = 200 }

The z-score of Third condition is calculated as;

Since we are given that a score of 48 on a test with $\bar X$ = 57 and s = 6,

So, z-score = $\frac{48-57}{6}$ = -1.5 {where $\bar X = 57$ and s = 6 }

AS we can clearly see that the z score of First and third condition are equally likely higher as compared to Second condition so it can be stated that A score of 2.6 on a test with $\bar X$ = 5.0 and s = 1.6 and A score of 48 on a test with $\bar X$ = 57 and s = 6 indicate the highest relative position.

7 0

3 years ago

A movie theater determines its profit, in dollars, using the expression 10n - 1000, where n is the number of tickets sold.

Alja [10]

Answer:

E

600

Step-by-step explanation:

10n - 1000 = 5000

10n = 6000

n = 600

HOPE THIS HELPS

PLZZ MARK BRAINLIEST

7 0

2 years ago