Answer: 4.4 x 10^-7
Explanation:
The dissociation equation for this reaction is:
MgCO3 (s) → Mg+2 (aq) + CO3-2 (aq)
(Here 0.08 >>> x )
So the solubility MgCO₃ in a solution that containing 0.080 M Mg²⁺ is 4.4 x 10^-7
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Taking into account the definition of molarity, the molarity of solution of sodium sulfate is 0.0732 .
Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
Molarity is expressed in units .
In this case, you have:
- number of moles of sodium sulfate=
(being 142 g/mole the molar mass of sodiums sulfate)
- volume= 500 mL= 0.5 L (being 1000 mL= 1 L)
Replacing in the definition of molarity:
Solving:
Molarity= 0.0732
Finally, the molarity of solution of sodium sulfate is 0.0732 .
Learn more about molarity: