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ASHA 777 [7]
2 years ago
11

4. The equation for the decomposition of hydrogen peroxide is shown. 2H₂O₂(aq) → 2H₂O(l) + O₂(g) 48.0 25.0 cm³ of aqueous hydrog

en peroxide forms 48.0 cm³ of oxygen at room temperature and pressure (r.t.p.). Calculate the concentration i aqueous hydrogen peroxide at the start of the experiment using the following steps ● Calculate the number of moles of oxygen formed. • Deduce the number of moles of hydrogen peroxide that decomposed. • Calculate the concentration of hydrogen peroxide in mol/dm³.​
Chemistry
1 answer:
Maksim231197 [3]2 years ago
8 0

Answer:

Just add what they equal to hope this helps :)

Explanation:

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Answer:Four types of vaccines are currently available: Live virus vaccines use the weakened (attenuated) form of the virus. The measles, mumps, and rubella (MMR) vaccine and the varicella (chickenpox) vaccine are examples

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10 points<br><br> How many more oxygen atoms are in 3Mg3(PO4)2 than in 4Al2O3?
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Answer:

12 more oxygen

Explanation:

An atom is the smallest particles that can take part in a chemical reaction

The given compounds are:

        3Mg₃(PO₄)₂  

 Number of oxygen atoms  = 3[2 x 4]  = 24 oxygen atoms

For;

             4Al₂O₃;

   Number of oxygen atoms  = 4 x 3  = 12 oxygen atoms

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3 years ago
What is the vapor pressure of the solution if 35.0 g of water is dissolved in 100.0 g of ethyl alcohol at 25 ∘C? The vapor press
masya89 [10]

<u>Answer:</u> The vapor pressure of the solution is 43.55 mmHg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For water:</u>

Given mass of water = 35.0 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{35.0g}{18g/mol}=1.944mol

  • <u>For ethyl alcohol:</u>

Given mass of ethyl alcohol = 100.0 g

Molar mass of ethyl alcohol = 46 g/mol

Putting values in equation 1, we get:

\text{Moles of ethyl alcohol}=\frac{100.0g}{46g/mol}=2.174mol

Total moles of solution = [1.944 = 2.174] moles = 4.118 moles

  • Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

<u>For water:</u>

\chi_{\text{water}}=\frac{n_{\text{water}}}{n_{\text{water}}+n_{\text{ethyl alcohol}}}

\chi_{water}=\frac{1.944}{4.118}=0.472

<u>For ethyl alcohol:</u>

\chi_{\text{ethyl alcohol}}=\frac{n_{\text{ethyl alcohol}}}{n_{\text{water}}+n_{\text{ethyl alcohol}}}

\chi_{\text{ethyl alcohol}}=\frac{2.174}{4.118}=0.528

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the vapor pressure of the solution, we use the law given by Dalton, which is:

P_T=\sum_{i=1}^n (p_i\times \chi_i)

Or,

P_T=[(p_{\text{water}}\times \chi_{\text{water}})+(p_{\text{ethyl alcohol}}\times \chi_{\text{ethyl alcohol}}

We are given:

Vapor pressure of water = 23.8 mmHg

Vapor pressure of ethyl alcohol = 61.2 mmHg

Putting values in above equation, we get:

p_T=[(23.8\times 0.472)+(61.2\times 0.528)]\\\\p_T=43.55mmHg

Hence, the vapor pressure of the solution is 43.55 mmHg

4 0
4 years ago
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