4. The equation for the decomposition of hydrogen peroxide is shown. 2H₂O₂(aq) → 2H₂O(l) + O₂(g) 48.0 25.0 cm³ of aqueous hydrog
1 answer:
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Answer:
hello your question lacks the required reaction pairs below are the missing pairs
Reaction system 1 :
A + B ⇒ D
A + B ⇒ U
Reaction system 2
A + B ⇒ D
B + D ⇒ U
Answer : reaction 1 : description of the reactor system : The desired reaction which is the first reaction possess a higher activation energy and higher temperature is required to kickstart reaction 1
condition to maximize selectivity : To maximize selectivity the concentration of reaction 1 should be higher than that of reaction 2
reaction 2 :
description of reactor system : The desired reaction i.e. reaction 1 has a lower activation energy and lower temperatures is required to kickstart reaction 1
condition to maximize selectivity:
to increase selectivity the concentration of D should be minimal
Explanation:
Reaction system 1 :
A + B ⇒ D
A + B ⇒ U
the selectivity of D is represented using the relationship below
hence SDu = 1/10 *
description of the reactor system : The desired reaction which is the first reaction possess a higher activation energy and higher temperature is required to kickstart reaction 1
condition to maximize selectivity : To maximize selectivity the concentration of reaction 1 should be higher than that of reaction 2
Reaction system 2
A + B ⇒ D
B + D ⇒ U
selectivity of D
hence Sdu =
description of reactor system : The desired reaction i.e. reaction 1 has a lower activation energy and lower temperatures is required to kickstart reaction 1
condition to maximize selectivity:
to increase selectivity the concentration of D should be minimal
Answer: The distance of the earth from the sun is
Explanation:
Speed of light =
Time taken to travel from sun to earth = 8.30 mins = (1min=60 s)
As we know ; Speed is defined as the distance travelled per unit time.
Hence distance between sun and earth =
Thus the distance of the earth from the sun is
Answer:
Two, KCl and PbCl₂.
Explanation:
Hello!
In this case, since the addition of chloride ions promote the following three ionic reactions:
We can infer that both silver chloride and lead (II) chloride are precipitated products as their Ksp are 6.56x10⁻⁴ and 1.59x10⁻⁵ respectively, which means they are merely soluble in water.
Best regards!