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cupoosta [38]
3 years ago
15

The goal of the following model is generate a clock waveform that has the clock high 4 time units and low 4 time units, with the

first rising edge at time 20. Submit a completed module which fills in the missing lines in q2 below:
module q2;
reg clock;
initial begin
clock=0
____
____
____
end
end
endmodule
Engineering
1 answer:
DedPeter [7]3 years ago
3 0

Answer:

module q2;

reg clock;

initial begin

clock = 0;

#20 clock = 1; // at 20 set high

always begin

#4 clock = ~clock; // then every four units change

end

end

endmodule

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aksik [14]

Answer:

Tmax=14.5MPa

Tmin=10.3MPa

Explanation:

T = 600 * 0.15 = 90N.m

T_max =\frac{T_c}{j}  = \frac{x}{y}  = \frac{90 \times 0.0175}{\frac{\pi}{2} \times (0.0175^4-0.0125^4)}

=14.5MPa

T_{min} =\frac{T_c}{j}  = \frac{x}{y}  = \frac{90 \times 0.0125}{\frac{\pi}{2} \times (0.0175^4-0.0125^4)}

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  Light = A xor B

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  Light = A xor B

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Air is compressed in a reversible, isothermal, steady- flow process from 15 psia, 100°F to 100 psia. Calculate the work of compr
mixas84 [53]

Answer:

|W|=169.28 KJ/kg

ΔS = -0.544 KJ/Kg.K

Explanation:

Given that

T= 100°F

We know that

1 °F = 255.92 K

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P _1= 15 psia

P _1= 100 psia

We know that work for isothermal process  

W=mRT\ln \dfrac{P_1}{P_2}

Lets take mass is 1 kg.

So work per unit mass

W=RT\ln \dfrac{P_1}{P_2}

We know that for air R=0.287KJ/kg.K

W=RT\ln \dfrac{P_1}{P_2}

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W= - 169.28 KJ/kg

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3 0
3 years ago
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