Answer:
For any material if ∈ is the axial strain then the lateral strain is given by -μ∈ is the lateral strain in the object
Where,
μ is the poisson's ratio of the material
The longitudinal strain is calculated as follows

Thus the lateral strain becomes

now by definition of lateral strain we have

By hookes law the stress developed due to the given strain is given by

Applying values we get

Thus the force is calculated as

Answer:
a) 254.6 GPa
b) 140.86 GPa
Explanation:
a) Considering the expression of rule of mixtures for upper-bound and calculating the modulus of elasticity for upper bound;
Ec(u) = EmVm + EpVp
To calculate the volume fraction of matrix, 0.63 is substituted for Vp in the equation below,
Vm + Vp = 1
Vm = 1 - 0.63
Vm = 0.37
In the first equation,
Where
Em = 68 GPa, Ep = 380 GPa, Vm = 0.37 and Vp = 0.63,
The modulus of elasticity upper-bound is,
Ec(u) = EmVm + EpVp
Ec(u) = (68 x 0.37) + (380 x 0.63)
Ec(u) = 254.6 GPa.
b) Considering the express of rule of mixtures for lower bound;
Ec(l) = (EmEp)/(VmEp + VpEm)
Substituting values into the equation,
Ec(l) = (68 x 380)/(0.37 x 380) + (0.63 x 68)
Ec(l) = 25840/183.44
Ec(l) = 140.86 GPa
Answer:According to NEC 220.12,
“the floor area shall be calculated from outside dimensions of the buildings, dwelling unit, or other area involved.
The area should not include open porches, garages or unused or unfinished spaces not adaptable for future use”.
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Explanati
Answer:
c from transmitter to a receiver