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Levart [38]
3 years ago
15

A stone-filled pit used for waste disposal is commonly referred to as a

Engineering
1 answer:
Talja [164]3 years ago
8 0

Answer:

<h2><em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>=</em><em>Soak pit / Soakage pit</em></h2>
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Which option identifies the requirement standard NOT met in the following scenario?
LenaWriter [7]

Answer:

The requirement does not meet the feasibility standard.

Explanation:

because the people can just put on the blackbelts

4 0
3 years ago
A motor whose pulley is 80mm in diameter is rotating at 30 revolutions per minute and is connected by a belt to another pulley o
Firdavs [7]

Answer:

169

Explanation:

ye men thats the answer

8 0
3 years ago
Air modeled as an ideal gas enters a combustion chamber at 20 lbf/in.2
motikmotik

Answer:

The answer is "112.97 \ \frac{ft}{s}"

Explanation:

Air flowing into thep_1 = 20 \ \frac{lbf}{in^2}

Flow rate of the mass m  = 230.556 \frac{lbm}{s}

inlet temperature T_1 = 700^{\circ} F

PipelineA= 5 \times 4 \ ft

Its air is modelled as an ideal gas Apply the ideum gas rule to the air to calcule the basic volume v:

\to \bar{R} = 1545 \ ft \frac{lbf}{lbmol ^{\circ} R}\\\\ \to M= 28.97 \frac{lb}{\bmol}\\\\ \to pv=RT \\\\\to v= \frac{\frac{\bar{R}}{M}T}{p}

      = \frac{\frac{1545}{28.97}(70^{\circ}F+459.67)}{20} \times \frac{1}{144}\\\\=9.8 \frac{ft3}{lb}

V= \frac{mv}{A}

   = \frac{230.556 \frac{lbm}{s} \times 9.8 \frac{ft^3}{lb}}{5 \times 4 \ ft^2}\\\\= 112.97 \frac{ft}{s}

8 0
3 years ago
Now design a BJT circuit which turns a red LED on when the room lights are off.
Alenkasestr [34]

Answer:

Materials -> R1 = 100 Ω, NPN BJT 2N2222, R3 = light-sensitive resistor, R4 = 120 KΩ, 5 V battery, red led

Design -> please see the image attached

Explanation:

We use LTspice to simulate the circuit that consists of a voltage divider in the gate of the transistor to change the operation region of the BJT accordingly to the resistance of the light-sensitive resistor; when R3 (light-sensitive resistor) has low resistance the voltage of the gate and emitter is approximately the same and the transistor is in a Cut-off state, when R3 increases its resistance the voltage of the gate start to rise and as a result, there is in a Forward-active state; a diode is placed on the collector with a small resistance R1 and whenever the transistor is active the led is going to turn on.

Note: If you need more current for the led you could reduce the value of R4, this will produce that lower values of R3 activate the transistor, you can adjust the circuit just by changing the value of R4, therefore, I highly recommend to use a potentiometer for R4 in the range of 10-300 K.

3 0
4 years ago
What is 68000/16496720
melisa1 [442]
It’s 2036391916472910376201
5 0
3 years ago
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