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slega [8]
3 years ago
11

Rank the four gases (air, exhaled air, gas produced from the decomposition of H2O2, gas from decomposition of NaHCO3) in order o

f decreasing concentration of oxygen).
Chemistry
1 answer:
ddd [48]3 years ago
4 0
<span>air = 70 % N2 exhaled air =70%N2 + some less O2 compared to only air 2H2O2=2H2O+O2 NaHCO3=2NaHCO3 → Na2CO3 + H2O + CO2 = No O2 gas from decomposition ssoooo NaHCO3 <exhaled air <air <H2O2

SO sorry for the long wait, hope I helped. 

</span>
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3. What is the mass of an object with a volume of 4 L and a density of 1.25 g/mL?
ch4aika [34]

Answer:

5000g

Explanation:

mass= density × volume

Since the unit of density here is g/mL, we need to convert the volume to mL.

1L= 1000mL

4L= 4 ×1000 = 4000 mL

Mass of object

= 1.25 ×4000

= 5000g

3 0
3 years ago
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A charged rubber rod can pick up a small neutrally charged piece of paper by what process
seropon [69]
Ion induced dipole process
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Why is 99 not a prime number​
Mice21 [21]

Explanation:

99 is not a prime number because it can be multiplied by itself and by other numbers

99*1

9*11

6 0
3 years ago
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A sample of methane (CH4) has a volume of 25 mL at a pressure of 0.80 atm. What is the volume of the gas at each of the followin
Xelga [282]

Answer:

a. 50ml b.10ml c. 6.097ml d. 190.1 ml

Explanation:

According to Boyle's law

Volume is inversely proportional to pressure at constant temerature

Mathematically

P1V1=P2V2

P1=Initial pressure=0.8atm

V1=Initial volume=25ml

making V2 the subject

at 0.4atm P2=0.4 atm,

V2=25×0.8/0.4

=50ml

at 2 atm V2=25×0.8/2

=10 ml

1mmHg=0.00131579

2500mmHg=3.28 atm

At 3.28 atm,V2=25×0.8/3.28

=6.097 ml

at 80.0 torr

1 torr=0.00131579

80 torr=0.1052 atm

at 0.1048 atm V2=25×0.8/0.1048

=190.1 ml

4 0
3 years ago
One mole of carbon will have the same number of particles as one mole of hydrogen.
AVprozaik [17]
And the answer is False,it does not have the same number with particles as the one mole of hydrogen.
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3 years ago
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