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3 years ago

Why are the molecules of hydrocarbons nonpolar?

2 answers:

7 0

Because hydrocarbons consist only C-H bonds, which are non-polar. When you look at the table of electronegativity (Pauling scale), you see, that the difference between the electronegativities of carbon and hydrogen is much smaller than that of nitrogen and hydrogen.

laiz [17]3 years ago

4 0

This is not the case in the hydrocarbon tail. The electronegativity of hydrogen and carbon are very similar, so the electron cloud is distributed evenly over the two atoms. Carbon-hydrogen bonds are said to be non-polar because they do not have positive and negative poles within themselves. Hope this helps.

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The mass of a block is 12 grams and the volume is 6 ml. Calculate the density of the

KengaRu [80]

Answer:

The density of block is 2 g/mL.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

mass of block = 12 g

volume = 6 mL

density = ?

Now we will put the values in the formula,

d= m/v

d = 12 g/ 6 mL

d = 2 g/mL

so, the density of block is 2 g/mL .

3 0

3 years ago

For a first-order reaction, A → B, the rate coefficient was found to be 3.4 × 10-4 s-1 at 23 °C. After 5.0 h, the concentration

Illusion [34]

Answer:

the original concentration of A = 0.0817092 M

Explanation:

A reaction is considered to be of first order it it strictly obeys the graphical equation method.

$k_1 = \dfrac{2.303}{t}log \dfrac{a}{a-x}$

where;

k = the specific rate coefficient = 3.4 × 10⁻⁴ s⁻¹

t = time = 5.0 h = 5.0 × 3600 = 18000 seconds

a = initial concentration = ???

a - x = remaining concentration of initial concentration at time t = 0.00018 mol L⁻¹

$3.4 \times 10^{-4}= \dfrac{2.303}{18000}log \dfrac{a}{0.00018}$

$3.4 \times 10^{-4}= 1.27944 \times 10^{-4} \times log \dfrac{a}{0.00018}$

$\dfrac{3.4 \times 10^{-4}}{1.27944 \times 10^{-4}}= log \dfrac{a}{0.00018}$

$2.657= log \dfrac{a}{0.00018}$

$10^{2.657}= \dfrac{a}{0.00018}$

$453.94 = \dfrac{a}{0.00018}$

$a =453.94 \times 0.00018$

a = 0.0817092 M

Thus , the original concentration of A = 0.0817092 M

8 0

3 years ago

Write insoluble or soluble solution for the following mixtores 1 2 3 4 5

dimaraw [331]

Gasoline in water = insoluble

acetone in nail polished = soluble

salt in alcohol = soluble

oil in vinegar = insoluble

tawas in water = soluble...

Sorry if i am incorrect......

6 0

2 years ago

If 13.0 g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?

Paul [167]

6.349 g mass of anhydrous magnesium sulfate will remain.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 1023 of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Molar mass MgSO₄.7 H₂O = 246.52 g/mol

$Moles =\frac{mass}{molar \;mass}$