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Andrews [41]
3 years ago
10

What else is produced during the combustion of propane, C3Hg? C3H8 +502 - 3C02 + 4

Chemistry
1 answer:
Finger [1]3 years ago
8 0
The products of a combustion reaction is always CO2 + H20, then you would balance it out with the whole equation.

In this case it would be:

C3H8 + O2 -> CO2 + H2O

Balanced:

C3H8 + 5O2 -> 3CO2 + 4H2O

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3 years ago
When 1.98g of a hydrocarbon is burned in a bomb calorimeter, the temperature increases by 2.06∘C. If the heat capacity of the ca
schepotkina [342]

Answer:

8.3 kJ

Explanation:

In this problem we have to consider that both water and the calorimeter absorb the heat of combustion, so we will calculate them:

q for water:

q H₂O = m x c x ΔT where m: mass of water = 944 mL x 1 g/mL = 944 g

                                      c: specific heat of water = 4.186 J/gºC

                                     ΔT : change in temperature = 2.06 ºC

so solving for q :

q H₂O = 944 g x 4.186 J/gºC x 2.06 ºC = 8,140 J

For calorimeter

q calorimeter  = C x  ΔT  where C: heat capacity of calorimeter = 69.6 ºC

                                     ΔT : change in temperature = 2.06 ºC

q calorimeter = 69.60J x 2.06 ºC = 143.4 J

Total heat released = 8,140 J +  143.4 J = 8,2836 J

Converting into kilojoules by dividing by 1000 we will have answered the question:

8,2836 J x 1 kJ/J = 8.3 kJ

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3 years ago
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Answer:

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Don’t worry about it, let me do your homework!

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Answer:

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