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Natali [406]
3 years ago
9

During photosynthesis, plants take in carbon dioxide and water and convert it into glucose and oxygen. If a plant makes 30 grams

of glucose (C6H12O6), how many moles of glucose has it produced?
A. 0.17 moles

B. 6 moles

C. 3 moles

D. 0.6 moles
Chemistry
1 answer:
kiruha [24]3 years ago
3 0

Answer:

A. 0.17 moles

Explanation:

Every 10 grams Glucose to mol = 0.05551 mol

30 moles= 0.166503, round up to .17

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How many grams of NH3 can be produced from 12.0g of H2?
RSB [31]

Answer:

Balanced reaction:

3 H2 (g)  + N2 (g)  → 2 NH3 (g)

Use stoichiometry to convert g of H2 to g of NH3.  The process would be:

g H2 → mol H2 → mol NH3 → g NH3

12.0 g H2 x (1 mol H2 / 2.02 g H2) x (2 mol NH3 / 3 mol H2) x (17.03 g NH3 / 1 mol NH3) = 67.4 g NH3

Explanation: See above

Hope this helps, friend.

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What tuberculosis means "
labwork [276]

Answer:

it is a infectiousr bacterial disease characterized by the growth of nodules(tubercles) in tissues especially the lungs

3 0
3 years ago
What is the Bohr model for potassium?
Zolol [24]
This is Bohrs model for potassium

4 0
3 years ago
Read 2 more answers
3. Students measured the mass of the reactants and products for a combustion reaction they observed.
coldgirl [10]

Answer:

A. Students made a measurement error, because ending with more products is impossible.

Explanation:

The law of conversation of matter tells us that in a chemical reaction, matter is never created or destroyed, it's simply converted from one form to another. So the mass of reactants should always equal the mass of the products in a chemical reaction. If there is excess mass in the product, the students have made an error of some kind.

4 0
3 years ago
What amount of heat is released when the temperature of 450.0 g of a
Molodets [167]

Answer:

\boxed {\boxed {\sf 4038.48 \ Joules}}

Explanation:

Since we are given the mass, specific heat, and change in temperature, we should use this formula for heat:

q=mc\Delta T

The substance's mass is 450.0 grams, the specific heat is 1.264 J/g°C, and the  change in temperature is 7.1 °C.

m= 450.0 \ g \\c= 1.264 \ J/g \textdegree C\\\Delta T= 7.1 \ \textdegree C

Substitute the values into the formula.

q= (450.0 \ g)(1.264 \ J/g \textdegree C)(7.1 \ \textdegree C)

Multiply the first 2 values together. The grams will cancel out.

q= 568.8 \ J/ \textdegree C (7.1 \ \textdegree C)

Multiply again. This time, the degrees Celsius cancel out.

q= 4038.48 \ J

<u>4038.48 Joules</u> of heat energy are released.

5 0
3 years ago
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