When visiting some countries, you may see a person balancing a load on the head. Explain why the center of mass of the load need
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Answer:
v = √[gR (sin θ - μcos θ)]
Explanation:
The free body diagram for the car is presented in the attached image to this answer.
The forces acting on the car include the weight of the car, the normal reaction of the plane on the car, the frictional force on the car and the net force on the car which is the centripetal force on the car keeping it in circular motion without slipping.
Resolving the weight into the axis parallel and perpendicular to the inclined plane,
N = mg cos θ
And the component parallel to the inclined plane that slides the body down the plane at rest = mg sin θ
Frictional force = Fr = μN = μmg cos θ
Centripetal force responsible for keeping the car in circular motion = (mv²/R)
So, a force balance in the plane parallel to the inclined plane shows that
Centripetal force = (mg sin θ - Fr) (since the car slides down the plane at rest, (mg sin θ) is greater than the frictional force)
(mv²/R) = (mg sin θ - μmg cos θ)
v² = R(g sin θ - μg cos θ)
v² = gR (sin θ - μcos θ)
v = √[gR (sin θ - μcos θ)]
Hope this Helps!!!
Answer:
1960.32306 kg/s
Explanation:
m = Mass of water = 1 kg
g = Acceleration due to gravity = 9.81 m/s²
h = Height from which the water will fall
Potential Energy
One megawatts of power is required
So, flow rate
1960.32306 kg/s is required to produce a megawatt of power
You must throw the snow ball by velocity 9.43 m/s horizontally to
hit him
Explanation:
You throw the snow ball horizontally from a height 5.5 meters
Your favorite physics teacher is 10 m away from you
You hit him on the foot
1. The initial velocity of the ball is v
2. The vertical component of v is zero because you throw the ball
horizontally
3. The vertical distance h is 5.5 m
4. The horizontal distance x is 10 m
We need to find how fast you must throw the snow ball to hit him
→ h = t +
g t²
→ h = -5.5 m ⇒ height below the point of thrown
→ g = -9.8 m/s²
→ = 0 ⇒ vertical component of v
→ -5.5 = (0) t + (-9.8) t²
→ - 5.5 = -4.9 t²
Divide both sides by -4.9
→ t² = 1.12245
Take √ for both sides
→ t = 1.06 seconds
→ x = t
→ = v
→ x = 10 m , t = 1.06
→ 10 = v(1.06)
Divide both sides by 1.06
→ v = 9.43 m/s
You must throw the snow ball by velocity 9.43 m/s horizontally to
hit him
Learn more:
You can learn more about velocity in brainly.com/question/13103128
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